
Triiodide ions are generated in solution by the following (unbalanced) reaction in acidic solution:
IO3−(aq) + I−(aq) → I3−(aq)
Triiodide ion concentration is determined by titration with a sodium thiosulfate (Na2S2O3) solution. The products are iodide ion and tetrathionate ion (S4O6−).
a. Balance the equation for the reaction of IO3− with I− ions.
b. A sample of 0.6013 g of potassium iodate was dissolved in water. Hydrochloric acid and solid potassium iodide were then added. What is the minimum mass of solid KI and the minimum volume of 3.00 M HQ required to convert all of the IO3− ions to I− ions?
c. Write and balance the equation for the reaction of S2O32− with I3− in acidic solution.
d. A 25.00-mL sample of a 0.0100 M solution of KIO. is reacted with an excess of KI. It requires 32.04 mL of Na2S2O3 solution to titrate the I3− ions present. What is the molarity of the Na2S2O3 solution?
e. How would you prepare 500.0 mL of the KIO3 solution in part d using solid KIO3?
(a)

The balanced equation for the given reaction, minimum mass of
Concept introduction:
Steps followed to balance a redox (reduction-oxidation) reaction occurs in acidic medium,
- Redox reactions can be separated into two half-reactions, such as oxidation reaction and reduction reaction.
- Balancing of oxygen and hydrogen are carried out by adding water and ions in the half-reactions, and balance the number of electrons then make the number of electrons in oxidation and reduction reactions equal by multiplying by integers.
- Club the both half-reactions.
- Mole ratio between the reactants of a reaction are depends upon the coefficients of reactants in a balanced chemical equation.
- Equation for number of grams of a substance from its number of moles is,
- Equation for finding molarity of a solution is,
Answer to Problem 154CP
The balanced equations for the given reaction is,
Explanation of Solution
To determine: The balanced equations for the given reactions.
The chemical equation for the given redox reaction is,
Steps (I, II and III) followed for balance the redox equation,
I- Separate the redox reaction into two, such as oxidation and reduction.
Therefore,
Oxidation reaction is,
Reduction reaction is,
II- Balance the atoms and electrons in each half-reactions,
Balancing of oxygen and hydrogen are carried out by adding water and ions in the half-reactions
Equalizing the numbers of electrons in oxidation and reduction reactions,
III- club the both half-reactions into a single equation,
The same number of electrons and molecules in the both sides will cancel each other,
So, the balanced equation for the given equation is,
(b)

Interpretation:
The balanced equation for the given reaction, minimum mass of
Concept introduction:
Steps followed to balance a redox (reduction-oxidation) reaction occurs in acidic medium,
- Redox reactions can be separated into two half-reactions, such as oxidation reaction and reduction reaction.
- Balancing of oxygen and hydrogen are carried out by adding water and ions in the half-reactions, and balance the number of electrons then make the number of electrons in oxidation and reduction reactions equal by multiplying by integers.
- Club the both half-reactions.
- Mole ratio between the reactants of a reaction are depends upon the coefficients of reactants in a balanced chemical equation.
- Equation for number of grams of a substance from its number of moles is,
- Equation for finding molarity of a solution is,
Answer to Problem 154CP
The minimum mass of
Explanation of Solution
To determine: the minimum mass of
The mass of
Equation for number of moles of a substance is,
Therefore,
The number of moles of
The balanced equations for the given reaction is,
The mole ratio between
Therefore,
The number of moles of
Equation for number of grams of a substance from its number of moles is,
Therefore,
The minimum mass of
The number of moles of
The volume of
That is,
(c)

Interpretation:
The balanced equation for the given reaction, minimum mass of
Concept introduction:
Steps followed to balance a redox (reduction-oxidation) reaction occurs in acidic medium,
- Redox reactions can be separated into two half-reactions, such as oxidation reaction and reduction reaction.
- Balancing of oxygen and hydrogen are carried out by adding water and ions in the half-reactions, and balance the number of electrons then make the number of electrons in oxidation and reduction reactions equal by multiplying by integers.
- Club the both half-reactions.
- Mole ratio between the reactants of a reaction are depends upon the coefficients of reactants in a balanced chemical equation.
- Equation for number of grams of a substance from its number of moles is,
- Equation for finding molarity of a solution is,
Answer to Problem 154CP
The balanced equation for the reaction between
Explanation of Solution
To determine: the balanced equations for the reaction between
The chemical equation for the given redox reaction is,
Steps (I, II and III) followed for balance the redox equation,
I- Separate the redox reaction into two, such as oxidation and reduction.
Therefore,
Oxidation reaction is,
Reduction reaction is,
II- Balance the atoms and electrons in each half-reactions,
Balancing of oxygen and hydrogen are carried out by adding water and ions in the half-reactions
Equalizing the numbers of electrons in oxidation and reduction reactions,
III- club the both half-reactions into a single equation,
The same number of electrons and molecules in the both sides will cancel each other,
So, the balanced equation for the given equation is,
To determine: the molarity of
(d)

Interpretation:
The balanced equation for the given reaction, minimum mass of
Concept introduction:
Steps followed to balance a redox (reduction-oxidation) reaction occurs in acidic medium,
- Redox reactions can be separated into two half-reactions, such as oxidation reaction and reduction reaction.
- Balancing of oxygen and hydrogen are carried out by adding water and ions in the half-reactions, and balance the number of electrons then make the number of electrons in oxidation and reduction reactions equal by multiplying by integers.
- Club the both half-reactions.
- Mole ratio between the reactants of a reaction are depends upon the coefficients of reactants in a balanced chemical equation.
- Equation for number of grams of a substance from its number of moles is,
- Equation for finding molarity of a solution is,
Answer to Problem 154CP
The molarity of
Explanation of Solution
The molarity of
The volume of
Equation for number of moles of a substance from its molarity and volume is,
Therefore,
The number of moles of
The balanced equations for the reaction of
The mole ratio between
Therefore,
The number of moles of
The balanced equations for the reaction between
The mole ratio between
Therefore,
The number of moles of
To explain: the preparation of
(e)

Interpretation:
The balanced equation for the given reaction, minimum mass of
Concept introduction:
Steps followed to balance a redox (reduction-oxidation) reaction occurs in acidic medium,
- Redox reactions can be separated into two half-reactions, such as oxidation reaction and reduction reaction.
- Balancing of oxygen and hydrogen are carried out by adding water and ions in the half-reactions, and balance the number of electrons then make the number of electrons in oxidation and reduction reactions equal by multiplying by integers.
- Club the both half-reactions.
- Mole ratio between the reactants of a reaction are depends upon the coefficients of reactants in a balanced chemical equation.
- Equation for number of grams of a substance from its number of moles is,
- Equation for finding molarity of a solution is,
Answer to Problem 154CP
The preparation of
Explanation of Solution
The molarity of
The volume of
Equation for number of moles of a substance from its molarity and volume is,
Therefore,
The number of moles of
Equation for number of grams of a substance from its number of moles is,
Therefore,
The mass of solid
Dissolving
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Chapter 4 Solutions
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