Concept explainers
Interpretation:
The IUPAC name of
Concept introduction:
The IUPAC name of a compound is made up of three parts: prefix, root, and suffix. If the compound contains different
If any chiral carbons are present, their absolute configurations are determined on the basis of Cahn-Ingold-Prelog rules and listed at the start along with the carbon number.
Answer to Problem F.1P
The IUPAC name of
Explanation of Solution
The structure of
The highest priority function group in
There are two other functional groups,
The root carbons are numbered from the carboxylic acid carbon as shown below.
This puts the amino group on C2 and the carbamoyl on C3. The carbon to which the amine group is attached is a chiral carbon. Based on the Cahn-Ingold-Prelog rules, the absolute configuration at this carbon is S.
Apparently, the three highest priority groups are arranged clockwise, but with the lowest priority hydrogen pointing toward the observer. Therefore, the actual configuration is S.
Therefore, the complete IUPAC name of
The highest priority functional group is considered as suffix, and the other remaining groups are considered as substituents for writing IUPAC name of the molecule.
Want to see more full solutions like this?
Chapter F Solutions
Organic Chemistry: Principles and Mechanisms (Second Edition)
- Try: Draw possible resonance contributing structures for the following organic species: CH3CH2NO2 [CH2CHCH2] [CH2CHCHO] [CH2CHCH2] [CH2CHNH2]arrow_forwardComplete the following synthesis. (d). H+ ง сarrow_forwardCan the target compound be efficiently synthesized in good yield from the substituted benzene of the starting material? If yes, draw the synthesis. Include all steps and all reactants.arrow_forward
- This is a synthesis question. Why is this method wrong or worse than the "correct" method? You could do it thiss way, couldn't you?arrow_forwardTry: Draw the best Lewis structure showing all non-bonding electrons and all formal charges if any: (CH3)3CCNO NCO- HN3 [CH3OH2]*arrow_forwardWhat are the major products of the following reaction? Draw all the major products. If there are no major products, then there is no reaction that will take place. Use wedge and dash bonds when necessary.arrow_forward
- IX) By writing the appropriate electron configurations and orbital box diagrams briefly EXPLAIN in your own words each one of the following questions: a) The bond length of the Br2 molecule is 2.28 Å, while the bond length of the compound KBr is 3.34 Å. The radius of K✶ is 1.52 Å. Determine the atomic radius in Å of the bromine atom and of the bromide ion. Br = Br b) Explain why there is a large difference in the atomic sizes or radius of the two (Br and Br). Tarrow_forwardWhen 15.00 mL of 3.00 M NaOH was mixed in a calorimeter with 12.80 mL of 3.00 M HCl, both initially at room temperature (22.00 C), the temperature increased to 29.30 C. The resultant salt solution had a mass of 27.80 g and a specific heat capacity of 3.74 J/Kg. What is heat capacity of the calorimeter (in J/C)? Note: The molar enthalpy of neutralization per mole of HCl is -55.84 kJ/mol.arrow_forwardWhen 15.00 mL of 3.00 M NaOH was mixed in a calorimeter with 12.80 mL of 3.00 M HCl, both initially at room temperature (22.00 C), the temperature increased to 29.30 C. The resultant salt solution had a mass of 27.80 g and a specific heat capacity of 3.74 J/Kg. What is heat capacity of the calorimeter (in J/C)? Note: The molar enthalpy of neutralization per mole of HCl is -55.84 kJ/mol. Which experimental number must be initialled by the Lab TA for the first run of Part 1 of the experiment? a) the heat capacity of the calorimeter b) Mass of sample c) Ti d) The molarity of the HCl e) Tfarrow_forward
- Organic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage LearningChemistry for Today: General, Organic, and Bioche...ChemistryISBN:9781305960060Author:Spencer L. Seager, Michael R. Slabaugh, Maren S. HansenPublisher:Cengage Learning