
Concept explainers
(a)
Interpretation:
The structure of the molecule is to be drawn and the IUPAC name is to be provided that corresponds to the given trivial name.
Concept introduction:
Carboxylic acids are the compounds containing
The carbonyl carbon atom is always numbered as C1 and the numbering continues. The substituents, if any, attached to the carbon chain are names according to the alphabetical order and the lowest locator number.
The trivial names of carboxylic acids are in the general form alkionic acid, while the IUPAC names are in the general form alkanoic acid. The suffix ‘ionic’ is replaced by ‘noic’ in the IUPAC name.

Answer to Problem F.12P
The structure of the molecule that corresponds to the given trivial name
The IUPAC name of
Explanation of Solution
The given IUPAC name is
The portion ‘
The IUPAC name of
The structure of the compound is drawn and the IUPAC name of the compound is written that corresponds to the given trivial name.
(b)
Interpretation:
The structure of the molecule is to be drawn and the IUPAC name is to be provided that corresponds to the given trivial name.
Concept introduction:
Carboxylic acids are the compounds containing
The carbonyl carbon atom is always numbered as C1 and the numbering continues. The substituents, if any, attached to the carbon chain are names according to the alphabetical order and the lowest locator number.
The trivial names of carboxylic acids are in the general form alkionic acid, while the IUPAC names are in the general form alkanoic acid. The suffix ‘ionic’ is replaced by ‘noic’ in the IUPAC name.

Answer to Problem F.12P
The structure of the molecule that corresponds to the given trivial name
The IUPAC name of
Explanation of Solution
The given IUPAC name is
The prefix ‘2, 2-dimethyl’ indicates that the methyl group is attached at C2, and C2 carbon atoms of the butyric acid. The structure of
The trivial names of carboxylic acids are in the general form alkionic acid while the IUPAC names are in the general form alkanoic acid. The suffix ‘ionic’ is replaced by ‘noic’ in the IUPAC name.
The butyric acid is the trivial name, its IUPAC name is butanoic acid. Thus, the IUPAC name of
The structure of the compound is drawn and the IUPAC name of the compound is written that corresponds to the given trivial name.
(c)
Interpretation:
The structure of the molecule is to be drawn and the IUPAC name is to be provided that corresponds to the given trivial name.
Concept introduction:
Carboxylic acids are the compounds containing
The carbonyl carbon atom is always numbered as C1 and the numbering continues. The substituents, if any, attached to the carbon chain are names according to the alphabetical order and the lowest locator number.
The trivial names of carboxylic acids are in the general form alkionic acid, while the IUPAC names are in the general form alkanoic acid. The suffix ‘ionic’ is replaced by ‘noic’ in the IUPAC name.

Answer to Problem F.12P
The structure of the molecule that corresponds to the given trivial name
The IUPAC name of
Explanation of Solution
The given IUPAC name is
The prefix ‘2-amino’ indicates that
The trivial names of carboxylic acids are in the general form alkionic acid while the IUPAC names are in the general form alkanoic acid. The suffix ‘ionic’ is replaced by ‘noic’ in the IUPAC name.
The propionic acid is the trivial name; its IUPAC name is propanoic acid. Thus, the IUPAC name of
The structure of the compound is drawn and the IUPAC name of the compound is written that corresponds to the given trivial name.
(d)
Interpretation:
The structure of the molecule is to be drawn and the IUPAC name is to be provided that corresponds to the given trivial name.
Concept introduction:
Carboxylic acids are the compounds containing
The carbonyl carbon atom is always numbered as C1 and the numbering continues. The substituents, if any, attached to the carbon chain are names according to the alphabetical order and the lowest locator number.
The trivial names of carboxylic acids are in the general form alkionic acid, while the IUPAC names are in the general form alkanoic acid. The suffix ‘ionic’ is replaced by ‘noic’ in the IUPAC name.

Answer to Problem F.12P
The structure of the molecule that corresponds to the given trivial name
The IUPAC name of
Explanation of Solution
The given IUPAC name is
Note the stereochemistry about the doubly bonded carbon atoms. The two high-priority groups are on the same side of the double bond making it (Z) stereoisomer.
The prefix
As the longest carbon chain has four atoms, the root name for carboxylic acid is
The structure of the compound is drawn and the IUPAC name of the compound is written that corresponds to the given trivial name.
(e)
Interpretation:
The structure of the molecule is to be drawn and the IUPAC name is to be provided that corresponds to the given trivial name.
Concept introduction:
Carboxylic acids are the compounds containing
The carbonyl carbon atom is always numbered as C1 and the numbering continues. The substituents, if any, attached to the carbon chain are names according to the alphabetical order and the lowest locator number.
The trivial names of carboxylic acids are in the general form alkionic acid, while the IUPAC names are in the general form alkanoic acid. The suffix ‘ionic’ is replaced by ‘noic’ in the IUPAC name.

Answer to Problem F.12P
The structure of the molecule that corresponds to the given trivial name
The IUPAC name of
Explanation of Solution
The given IUPAC name is
The prefix ‘diethyl’ in the name suggests that an ethyl group is attached at C2 carbon atom of the root. The locator numbers 2 and 2 are not included in the name because there is only one carbon atom to which any substituent could get attached. Thus, the complete structure of
As the longest carbon chain has three atoms, the root name for this dicarboxylic acid is
The structure of the compound is drawn and the IUPAC name of the compound is written that corresponds to the given trivial name.
Want to see more full solutions like this?
Chapter F Solutions
Organic Chemistry: Principles and Mechanisms (Second Edition)
- For each reaction below, decide if the first stable organic product that forms in solution will create a new CC bond, and check the appropriate box. Next, for each reaction to which you answered "Yes" to in the table, draw this product in the drawing area below. Note for advanced students: for this problem, don't worry if you think this product will continue to react under the current conditions - just focus on the first stable product you expect to form in solution. དྲ。 ✗MgBr ? O CI Will the first product that forms in this reaction create a new C-C bond? Yes No • ? Will the first product that forms in this reaction create a new CC bond? Yes No × : ☐ Xarrow_forwardPredict the major products of this organic reaction: OH NaBH4 H ? CH3OH Note: be sure you use dash and wedge bonds when necessary, for example to distinguish between major products with different stereochemistry. Click and drag to start drawing a structure. ☐ : Sarrow_forwardPredict the major products of this organic reaction: 1. LIAIHA 2. H₂O ? Note: be sure you use dash and wedge bonds when necessary, for example to distinguish between major products with different stereochemistry. Click and drag to start drawing a structure. X : ☐arrow_forward
- For each reaction below, decide if the first stable organic product that forms in solution will create a new C - C bond, and check the appropriate box. Next, for each reaction to which you answered "Yes" to in the table, draw this product in the drawing area below. Note for advanced students: for this problem, don't worry if you think this product will continue to react under the current conditions - just focus on the first stable product you expect to form in solution. NH2 tu ? ? OH Will the first product that forms in this reaction create a new CC bond? Yes No Will the first product that forms in this reaction create a new CC bond? Yes No C $ ©arrow_forwardAs the lead product manager at OrganometALEKS Industries, you are trying to decide if the following reaction will make a molecule with a new C-C bond as its major product: 1. MgCl ? 2. H₂O* If this reaction will work, draw the major organic product or products you would expect in the drawing area below. If there's more than one major product, you can draw them in any arrangement you like. Be sure you use wedge and dash bonds if necessary, for example to distinguish between major products with different stereochemistry. If the major products of this reaction won't have a new CC bond, just check the box under the drawing area and leave it blank. Click and drag to start drawing a structure. This reaction will not make a product with a new CC bond. G marrow_forwardIncluding activity coefficients, find [Hg22+] in saturated Hg2Br2 in 0.00100 M NH4 Ksp Hg2Br2 = 5.6×10-23.arrow_forward
- give example for the following(by equation) a. Converting a water insoluble compound to a soluble one. b. Diazotization reaction form diazonium salt c. coupling reaction of a diazonium salt d. indacator properties of MO e. Diazotization ( diazonium salt of bromobenzene)arrow_forward2-Propanone and ethyllithium are mixed and subsequently acid hydrolyzed. Draw and name the structures of the products.arrow_forward(Methanesulfinyl)methane is reacted with NaH, and then with acetophenone. Draw and name the structures of the products.arrow_forward
- 3-Oxo-butanenitrile and (E)-2-butenal are mixed with sodium ethoxide in ethanol. Draw and name the structures of the products.arrow_forwardWhat is the reason of the following(use equations if possible) a.) In MO preperation through diazotization: Addition of sodium nitrite in acidfied solution in order to form diazonium salt b.) in MO experiment: addition of sodium hydroxide solution in the last step to isolate the product MO. What is the color of MO at low pH c.) In MO experiment: addition of sodium hydroxide solution in the last step to isolate the product MO. What is the color of MO at pH 4.5 d.) Avoiding not cooling down the reaction mixture when preparing the diazonium salt e.) Cbvcarrow_forwardA 0.552-g sample of an unknown acid was dissolved in water to a total volume of 20.0 mL. This sample was titrated with 0.1103 M KOH. The equivalence point occurred at 29.42 mL base added. The pH of the solution at 10.0 mL base added was 3.72. Determine the molar mass of the acid. Determine the Ka of the acid.arrow_forward
- World of Chemistry, 3rd editionChemistryISBN:9781133109655Author:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCostePublisher:Brooks / Cole / Cengage LearningChemistry for Today: General, Organic, and Bioche...ChemistryISBN:9781305960060Author:Spencer L. Seager, Michael R. Slabaugh, Maren S. HansenPublisher:Cengage Learning
- Organic Chemistry: A Guided InquiryChemistryISBN:9780618974122Author:Andrei StraumanisPublisher:Cengage LearningIntroductory Chemistry: An Active Learning Approa...ChemistryISBN:9781305079250Author:Mark S. Cracolice, Ed PetersPublisher:Cengage Learning



