Chapter 9.9, Problem 14PSB

a

To determine

To find:The value of $\cos \angle BRM$

Answer to Problem 14PSB

The value of $\cos \angle BRM=\frac{3}{5}$

Explanation of Solution

Given information:The following information has been given

  $RO=18$

  $HM=24$

Formula used:Pythagoras theorem has been used

Calculation:We apply the Pythagoras theorem in the triangle MBR where B is the midpoint of RO and HM, we get

  $9^2+{12}^2=R{M}^2$

Hence, we get

  $RM=15$

Now, we use the cosine formula to get

  $\cos \angle BRM=\frac{BR}{RM}$

Hence, we get

  $\cos \angle BRM=\frac{3}{5}$

b

To determine

To find:The value of $\tan \angle BHO$

Answer to Problem 14PSB

The value of $\tan \angle BHO=\frac{9}{12}$

Explanation of Solution

Given information:The following information has been given

  $RO=18$

  $HM=24$

Formula used:Basic trigonometric identity has been used

Calculation:we apply the tangent formula in the triangle BHO where B is the midpoint of RO and HM, we get

  $\tan \angle BHO=\frac{BO}{BH}$

Hence, we get

  $\tan \angle BHO=\frac{9}{12}$