Chapter 9.10, Problem 2PSA

a

To determine

To find:The value of $m\angle A$ when $\sin \angle A=0.4067$ .

Answer to Problem 2PSA

The value of $m\angle A={24}^0$

Explanation of Solution

Given information:The following information has been given

  $\sin \angle A=0.4067$

We use the trigonometric tables given, to find the value of

  $\begin{array}{l}m\angle A={\sin }^{-1}0.4067\text{ [}{\sin }^{-1}0.4067={24}^0\text{]}\\ m\angle A={24}^o\end{array}$

Thus, we can say that

  $m\angle A={24}^0$

b

To determine

To find: The value of $m\angle A$ when $\tan \angle A=3.4874$ .

Answer to Problem 2PSA

The value of $m\angle A={74}^0$

Explanation of Solution

Given information:The following information has been given

  $\tan \angle A=3.4874$

We use the trigonometric tables given, to find the value of

  $m\angle A={\tan }^{-1}3.4874$

Hence, we get

  ${\tan }^{-1}3.4874={74}^0$

Thus, we can say that

  $m\angle A={74}^0$

c

To determine

To find: The value of $m\angle A$ when $\cos \angle A=0.7071$ .

Answer to Problem 2PSA

The value of $m\angle A={45}^0$

Explanation of Solution

Given information:The following information has been given

  $\cos \angle A=0.7071$

We use the trigonometric tables given, to find the value of

  $m\angle A={\cos }^{-1}0.7071$

Hence, we get

  ${\cos }^{-1}0.7071={45}^0$

Thus, we can say that

  $m\angle A={45}^0$