Chapter 9.6, Problem 7PSA

To determine

To Calculate: The perimeter of an isosceles triangle.

Answer to Problem 7PSA

The perimeter of an isosceles triangle is $50$

Explanation of Solution

Given information: Base “ b ” and height “ h ”of an isosceles triangle are $16$ dm and $15$ dm

Formula used:Here, we are using Pythagoras theorem

  ${\left(Hypotenuse\right)}^2={\left(perpendicular\right)}^2+{\left(base\right)}^2$

Calculation:

  

Here, the formula is

  ${\left(Hypotenuse\right)}^2={\left(perpendicular\right)}^2+{\left(base\right)}^2$

  ${\left(AC\right)}^2={\left(AD\right)}^2+{\left(DC\right)}^2$

  →${\left(AC\right)}^2={\left(15\right)}^2+{\left(8\right)}^2$

  →$AC=\sqrt{225+64}$

Hence, perimeter = $17+17+16$

  →$50$

Conclusion: Hence,the perimeter of an isosceles triangle is $50$