Chapter 9.5, Problem 22PSB

To determine

To calculate: The Distance travelled by rocket from launch to touchdown.

Answer to Problem 22PSB

Total distance travelled by rocket is $43$ m.

Explanation of Solution

Given information:Here, we have given that distance from point to ground (AC) is $20$ m and distance of rocket from launch side (BC) is $11$ m.

Formula used: Pythagoras Theorem: ${(P)}^2+{(B)}^2={(H)}^2$

Calculation: Total distance travelled by rocket is $AB+AC$ .

Now, $A{B}^2=A{C}^2+B{C}^2$ (By Pythagoras theorem)

  

  $\begin{array}{l}$ \Rightarrow A{B}^2={(20)}^2+{(11)}^2$\Rightarrow A{B}^2=400+121\\ \Rightarrow A{B}^2=521\\ \Rightarrow AB=\sqrt{521}\\ \Rightarrow AB=22.8\end{array}$

  $\Rightarrow AB=23$ m

Now, distance travelled by rocket = $(23+20)$ m

  $=43$ m