Chapter 9.6, Problem 8PSA

To determine

To Calculate: The length of the upper base of the isosceles trapezoid.

Answer to Problem 8PSA

Length of the upper base of the isosceles trapezoid is $27$

Explanation of Solution

Given information: Measures of lengths

AB = $15$

BC = $35$

Formula used:Here, we are using Pythagoras theorem

  ${\left(base\right)}^2={\left(perpendicular\right)}^2-{\left(hypotenuse\right)}^2$

Calculation:

  

Here, the formula is

  ${\left(base\right)}^2={\left(perpendicular\right)}^2-{\left(hypotenuse\right)}^2$

  ${\left(BC\right)}^2={\left(AC\right)}^2-{\left(AB\right)}^2$

  ${\left(BC\right)}^2=144-225$

  ${\left(BC\right)}^2=81$

  $BC=9$

Hence, $x=0$ and $2x=18$

And, length of upper base = $45-2x$

  →$45-18$

→27

Conclusion: Hence,the length of the upper base of the isosceles trapezoid is $27$