Chapter 9.3, Problem 8PSA

To determine

To find: The coordinates of the point $P$ .

Answer to Problem 8PSA

The coordinates of point $P$ are (3, 1).

Explanation of Solution

Given information :

  $P$ is the center of circle. And coordinates of the points $C$ and $D$ are $(-4,2)\text{ and }(10,0)$ . Here, $CD$ is the diameter of the circle.

Formula used :

Center of a circle divides the diameter in two equal parts.

Calculation :

Since, center of a circle divides the diameter in two equal parts. So, the coordinates of center $P$

  $\begin{array}{l}=\left(\frac{x_1+y_1}{2},\frac{x_2+y_2}{2}\right)\\ =\left(\frac{10-4}{2},\frac{2+0}{2}\right)\\ =\left(3,1\right)\end{array}$