Chapter 9.6, Problem 12PSA

To determine

To Calculate: The perimeter of the rhombus.

Answer to Problem 12PSA

The perimeter of the rhombus is $75.32$

Explanation of Solution

Given information:

RHOM is a rhombus with diagonals

  $RO=48$

  $HM=14$

Formula used:

Here, the formula is

Area of rhombus = $\frac{1}{2}\times d_1\times d_2$

Calculation:

  $RO=48$ and $HM=14$

Putting these values in the formula,

  $Area=\frac{1}{2}\times 48\times 14$

  $Area=336$

And, $Area=a^2$ (here, “a” is side)

  $336=a^2$

  $a=18.33$

And, perimeter = $4a$

  →$4\times 18.33$

  →$75.32$

Conclusion: Hence,the perimeter of the rhombus is $75.32$