Chapter 9.1, Problem 12PSB

To determine

To find:The value of AB to the nearest tenth has to be found

Answer to Problem 12PSB

The value of $AB=12.2$

Explanation of Solution

Given information:The following coordinates have been given

  $A=(0,7)$ , and

  $B=(10,0)$

Formula used:The value of a line segment will be

  $AB=\sqrt{{(x_2-x_1)}^2+{(y_2-y_1)}^2}$

Where x and y are the respective coordinates of the points A and B .

Calculation:We know that for the given line, the value can be calculated as

  $AB=\sqrt{{(x_2-x_1)}^2+{(y_2-y_1)}^2}$

Hence, we substitute the values of the coordinates in the above formula. We get

  $AB=\sqrt{7^2+{10}^2}=\sqrt{149}$

Now, rounding off it’s value to the nearest tenth, we get

  $AB=12.2$