Java: An Introduction to Problem Solving and Programming (8th Edition)
Java: An Introduction to Problem Solving and Programming (8th Edition)
8th Edition
ISBN: 9780134462035
Author: Walter Savitch
Publisher: PEARSON
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Chapter 9.2, Problem 18STQ
Program Plan Intro

Exception:

  • • It is nothing but an undesirable or unexpected event that occurs at run time which interrupts the normal flow of the program’s commands.
  • • Exception handling is a mechanism that handle runtime errors like “ClassNotFoundException”, “SQLException”, and so on.
  • • An advantage of exception handling is to maintain a flow of the program.
  • • An exception can be handled using “try” and “catch” block.

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1.public class Test{ public static void main(String args[]){ Person p = null; try{ } p.talk(); } catch (NullPointerException e) { System.out.print("There is a NullPointerException."); } catch(Exception e) { System.out.print("There is an Exception."); } System.out.print("Everything went fine."); } what will be the result if you run this program? O There is a NullPointerException. Everything went fine. O There is a NullPointerException. There is a NullPointerException. There is an Exception. This code will not compile, because in Java there are no pointers.
Suppose the exception class CrazyException is defined as follows: public class CrazyException extends Exception { public CrazyException() { super("Crazy exception thrown!"); System.out.println("Wow, Crazy exception thrown!"); } public CrazyException(String message) { super(message); System.out.println("Wow, crazy exception thrown with "+ "an argument!"); } public void crazyMethod() { System.out.println("Message is " + getMessage()); } } What output would be produced by the following unlikely code? CrazyException exceptionObject = new CrazyException(); System.out.println(exceptionObject.getMessage()); exceptionObject.crazyMethod();
Suppose the exception class TestException is defined as follows:public class TestException extends Exception{public TestException(){super("Test Exception thrown!");System.out.println("Test exception thrown!!");}public TestException(String message){super(message);System.out.println("Test exception thrown with an argument!");}public void testMethod(){System.out.println("Message is " + getMessage());}}What output would be produced by the following code (which is just anexercise and not likely to occur in a program)?TestException exceptionObject = new TestException();System.out.println(exceptionObject.getMessage());exceptionObject.testMethod();The class TestException is on the website that comes with this text.

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Java: An Introduction to Problem Solving and Programming (8th Edition)

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