Chapter 9, Problem 9.81SP

(a)

Interpretation Introduction

Interpretation:

The partial pressure of $\text{He}$ gas has to be calculated.

Concept Introduction:

Partial Pressure:

Dalton’s law of partial pressure states that “the total pressure (P) of the mixture is equal to the sum of the partial pressures ${\text{(P}}_{\text{A}}{\text{, P}}_{\text{B}}{\text{, P}}_{\text{C}}\mathrm{.....}\text{)}$ of all the component gases $\text{(A, B, C}\mathrm{......}\text{)}$  present in the mixture” and is given as,

${\text{P = P}}_{\text{A}}{\text{ + P}}_{\text{B}}{\text{ + P}}_{\text{C}}\text{ + }\mathrm{.......}$

The ideal gas law for the individual gas component A is given as,

${\text{P}}_{\text{A}}{\text{V = n}}_{\text{A}}\text{RT}$

Mole Fraction:

$\text{The mole fraction of A = }\frac{n_{\text{A}}}{n}=\frac{{\text{P}}_{\text{A}}}{\text{P}}$

Millimetres of mercury

Millimeters of mercury is a manometric unit of pressure, it is well-defined as the added pressure generated by a column of mercury one millimeter high. It is represented by the symbol $\text{mmHg}$.

$\text{1}\text{mmHg=}\frac{\text{1}}{\text{760}}\text{atm}$

(b)

Interpretation Introduction

Interpretation:

The partial pressure of $\text{Ar}$ gas has to be calculated.

Concept Introduction:

Partial Pressure:

Dalton’s law of partial pressure states that “the total pressure (P) of the mixture is equal to the sum of the partial pressures ${\text{(P}}_{\text{A}}{\text{, P}}_{\text{B}}{\text{, P}}_{\text{C}}\mathrm{.....}\text{)}$ of all the component gases $\text{(A, B, C}\mathrm{......}\text{)}$  present in the mixture” and is given as,

${\text{P = P}}_{\text{A}}{\text{ + P}}_{\text{B}}{\text{ + P}}_{\text{C}}\text{ + }\mathrm{.......}$

The ideal gas law for the individual gas component A is given as,

${\text{P}}_{\text{A}}{\text{V = n}}_{\text{A}}\text{RT}$

Mole Fraction:

$\text{The mole fraction of A = }\frac{n_{\text{A}}}{n}=\frac{{\text{P}}_{\text{A}}}{\text{P}}$

Millimetres of mercury

Millimeters of mercury is a manometric unit of pressure, it is well-defined as the added pressure generated by a column of mercury one millimeter high. It is represented by the symbol $\text{mmHg}$.

$\text{1}\text{mmHg=}\frac{\text{1}}{\text{760}}\text{atm}$