The portion of the structure of a sphingophospholipids that constitute its head in the “head and two tails” model has to be stated. Concept introduction: In sphingophospholipids, the platform molecule is sphingosine to which one fatty acid and one phosphate group are attached. An alcohol is attached to the phosphate group. There are two ester linkages and one amide linkage present in the structure of sphingophospholipids.
The portion of the structure of a sphingophospholipids that constitute its head in the “head and two tails” model has to be stated. Concept introduction: In sphingophospholipids, the platform molecule is sphingosine to which one fatty acid and one phosphate group are attached. An alcohol is attached to the phosphate group. There are two ester linkages and one amide linkage present in the structure of sphingophospholipids.
Solution Summary: The author explains the structure of a sphingophospholipid that has hydrophobic properties in the "head and two tails" model.
Interpretation: The portion of the structure of a sphingophospholipids that constitute its head in the “head and two tails” model has to be stated.
Concept introduction: In sphingophospholipids, the platform molecule is sphingosine to which one fatty acid and one phosphate group are attached. An alcohol is attached to the phosphate group. There are two ester linkages and one amide linkage present in the structure of sphingophospholipids.
(b)
Interpretation Introduction
Interpretation: The portion of the structure of a sphingophospholipid that have hydrophobic properties in the “head and two tails” model has to be stated.
Concept introduction: In sphingophospholipids, the platform molecule is sphingosine to which one fatty acid and one phosphate group are attached. An alcohol is attached to the phosphate group. There are two ester linkages and one amide linkage present in the structure of sphingophospholipids.
When talking about the acidity of carboxylic acids, is it the same thing to say higher or stronger acidity?
Using the following two half-reactions, determine the pH range in which $NO_2^-\ (aq)$ cannot be found as the predominant chemical species in water.* $NO_3^-(aq)+10H^+(aq)+8e^-\rightarrow NH_4^+(aq)+3H_2O(l),\ pE^{\circ}=14.88$* $NO_2^-(aq)+8H^+(aq)+6e^-\rightarrow NH_4^+(aq)+2H_2O(l),\ pE^{\circ}=15.08$
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