The solution of the equation
Answer to Problem 32CR
Explanation of Solution
Given:
The equation,
Concept Used:
- To get rid of a number in addition from one side, subtract the same number from both sides of equal sign.
- To get rid of a number in subtraction from one side, add the same number both sides of equal sign.
- To get rid of a number in multiplication from one side, divide the same number from both sides of equal sign.
- To get rid of a number in division from one side, multiply the same number both sides of equal sign.
Rules of Addition/ Subtraction:
- Two numbers with similar sign always get added and the resulting number will carry the similar sign.
- Two numbers with opposite signs always get subtracted and the resulting number will carry the sign of larger number.
Rules of Multiplication/ Division:
- The product/quotient of two similar sign numbers is always positive.
- The product/quotient of two numbers with opposite signs is always negative.
Calculation:
In order to solve the given equation
Here to isolate x on left side, first subtract both sides by
Thus, the solution of the given equation is
Chapter 8 Solutions
Glencoe Math Accelerated, Student Edition
Additional Math Textbook Solutions
Basic Business Statistics, Student Value Edition
Precalculus
Introductory Statistics
A First Course in Probability (10th Edition)
A Problem Solving Approach To Mathematics For Elementary School Teachers (13th Edition)
Pre-Algebra Student Edition
- i attached the question and the way i solved it, i believe i made an error, could you point it out for me because the correct answer is 3pi/2correct answer is D, please see both attached photosarrow_forwardQuestion 3 and 4arrow_forwardcould you explain this using stoke theoremi already circled the correct answerarrow_forward
- can you explain why the answer is 1/3arrow_forwardThe position of a particle that moves along the x-axis is defined by x = - 3t^2 + 12^t - 6 f, where t is in seconds. For the time interval t = 0 to t = 3 s, (1) plot the position, velocity, and acceleration as functions of time; (2) calculate the distance traveled; and (3) determine the displacement of the particleshow the graph and write the solution with a penarrow_forwardThe position of a particle that moves along the x-axis is defined by x = - 3t^2 + 12^t - 6 f, where t is in seconds. For the time interval t = 0 to t = 3 s, (1) plot the position, velocity, and acceleration as functions of time; (2) calculate the distance traveled; and (3) determine the displacement of the particleshow the graph and write the solution with a penarrow_forward
- The answer for number 1 is D Could you show me whyarrow_forwardThe path of a particle moving in a straight line is given by s = t^3 - 6t^2+ 9t + 4, where s is in ft and t in seconds. a. Finds and a when v = 0. b. Find s and v when a = 0.show the graph if needed and write the solution with a penarrow_forwardfind the roots it may help to know b =1arrow_forward
- Calculus: Early TranscendentalsCalculusISBN:9781285741550Author:James StewartPublisher:Cengage LearningThomas' Calculus (14th Edition)CalculusISBN:9780134438986Author:Joel R. Hass, Christopher E. Heil, Maurice D. WeirPublisher:PEARSONCalculus: Early Transcendentals (3rd Edition)CalculusISBN:9780134763644Author:William L. Briggs, Lyle Cochran, Bernard Gillett, Eric SchulzPublisher:PEARSON
- Calculus: Early TranscendentalsCalculusISBN:9781319050740Author:Jon Rogawski, Colin Adams, Robert FranzosaPublisher:W. H. FreemanCalculus: Early Transcendental FunctionsCalculusISBN:9781337552516Author:Ron Larson, Bruce H. EdwardsPublisher:Cengage Learning