Chapter 8.7, Problem 38IP

To determine

Write and solve an inequality to find the 2009 attendance.

Answer to Problem 38IP

  $x-809300\ge 16700$; The attendance in 2009 is at least 809000.

Explanation of Solution

Given:

The 2008 attendance at the Ohio State Fair was at least 16,700 less than the attendance in 2009. If the attendance in 2008 was 809,300, write and solve an inequality to find the 2009 attendance.

Concept Used:

The 2008 attendance at the Ohio State Fair was at least 16,700 less than the attendance in 2009.

Let x be represents the attendance in 2009.

In 2008 the attendance was 809,300.

The 2008 attendance at the Ohio State Fair was at least 16,700 less than the attendance in 2009.

At least means the symbol $\ge$

The required inequality is $x-809300\ge 16700$

Calculation:

Let x be represents the attendance in 2009.

The required inequality is $x-809300\ge 16700$

Now solve for x:

  $\begin{array}{l}x-809300\ge 16700\\ x-809300+809,300\ge 16,700+809,300\\ x\ge 826000\end{array}$

The attendance in 2009 is at least 809000.

Thus, the attendance in 2009 is at least 809000.