a) Interpretation: The major product obtainable from addition of HBr to methylidenecyclohexane is to be predicted. Concept introduction: The first step in the addition of HBr with alkenes is the formation of a stable carbocation by the attack of the π electrons of the double bond on the positively polarized hydrogen of HBr eliminating a bromide ion. In the second step the carbocation reacts with the bromide ion to yield the product. To predict: The major product obtainable from addition of HBr to methylidenecyclohexane.

Question

22

Answer 1

Question

Chapter 7.SE, Problem 58AP

Interpretation Introduction

a)

Interpretation:

The major product obtainable from addition of HBr to methylidenecyclohexane is to be predicted.

Concept introduction:

The first step in the addition of HBr with alkenes is the formation of a stable carbocation by the attack of the π electrons of the double bond on the positively polarized hydrogen of HBr eliminating a bromide ion. In the second step the carbocation reacts with the bromide ion to yield the product.

To predict:

The major product obtainable from addition of HBr to methylidenecyclohexane.

Interpretation Introduction

b)

Interpretation:

The major product obtainable from addition of HBr to the octahydronaphthalene is to be predicted.

Concept introduction:

The first step in the addition of HBr with alkenes is the formation of a stable carbocation by the attack of the π electrons of the double bond on the positively polarized hydrogen of HBr eliminating a bromide ion. In the second step the carbocation reacts with the bromide ion to yield the product.

To predict:

The major product obtainable from addition of HBr to octahydronaphthalene.

Interpretation Introduction

c)

Interpretation:

The major product obtainable from addition of HBr to 4-methyl-2-pentene is to be predicted.

Concept introduction:

In electrophilic addition reactions, the first step is the attack of the π electrons of the double bond on the hydrogen of another reactant to yield a carbocation. One of the carbon in C=C gets attached to hydrogen while the other acquires a positive charge. In the second step, the carbocation formed can rearrange to give another more stable carbocation either by a hydride shift (shift of hydrogen atom with its electron pair) or by an alkyl shift (shift of an alkyl group with its electron pair) between neighboring carbons. In the last step the carbocation produced reacts with a negatively charged ion or eliminates a proton to give the product.

To give:

The major product obtainable from addition of HBr to 4-methyl-2-pentene.

Expert Solution & Answer

Trending nowThis is a popular solution!

See solution

Check out sample textbook solution

Students have asked these similar questions

22

PLEASE READ!!! I DONT WANT EXAMPLES, I DONT WANT WORDS OR PARAGRAPHS FOR THE MECHANISM!!! THANKS First image: QUESTION 6. I have to show, with ARROWS and STRUCTURES, the mechanism of the reaction at the bottom. Also I have to show by mecanism why the reaction wouldn't work if the alcohol was primary. I also tried to draw the mechanism, tell me what to change. Please note that its an AMIDE thats formed not an AMINE the nitrogen has ONE hydrogen and one Phenyl-C-Phenyl. I already asked for this mechanism and got as a final product ...-NH2 not whats shown on the picture, thank you Ths second part. QUESTION 3. I just need a way to synthesize the lactone A, I already started please continue from where I left it Second image: I simply need the products, substrates or reagents, thank you

Indicate how to prepare a 10% sodium hydroxide (NaOH) solution to a slightly alkaline pH.

Answer 2

Question

Chapter 7.SE, Problem 58AP

Interpretation Introduction

a)

Interpretation:

The major product obtainable from addition of HBr to methylidenecyclohexane is to be predicted.

Concept introduction:

The first step in the addition of HBr with alkenes is the formation of a stable carbocation by the attack of the π electrons of the double bond on the positively polarized hydrogen of HBr eliminating a bromide ion. In the second step the carbocation reacts with the bromide ion to yield the product.

To predict:

The major product obtainable from addition of HBr to methylidenecyclohexane.

Interpretation Introduction

b)

Interpretation:

The major product obtainable from addition of HBr to the octahydronaphthalene is to be predicted.

Concept introduction:

The first step in the addition of HBr with alkenes is the formation of a stable carbocation by the attack of the π electrons of the double bond on the positively polarized hydrogen of HBr eliminating a bromide ion. In the second step the carbocation reacts with the bromide ion to yield the product.

To predict:

The major product obtainable from addition of HBr to octahydronaphthalene.

Interpretation Introduction

c)

Interpretation:

The major product obtainable from addition of HBr to 4-methyl-2-pentene is to be predicted.

Concept introduction:

In electrophilic addition reactions, the first step is the attack of the π electrons of the double bond on the hydrogen of another reactant to yield a carbocation. One of the carbon in C=C gets attached to hydrogen while the other acquires a positive charge. In the second step, the carbocation formed can rearrange to give another more stable carbocation either by a hydride shift (shift of hydrogen atom with its electron pair) or by an alkyl shift (shift of an alkyl group with its electron pair) between neighboring carbons. In the last step the carbocation produced reacts with a negatively charged ion or eliminates a proton to give the product.

To give:

The major product obtainable from addition of HBr to 4-methyl-2-pentene.

Expert Solution & Answer

Trending nowThis is a popular solution!

See solution

Check out sample textbook solution

Answer 3

Question

Chapter 7.SE, Problem 58AP

Interpretation Introduction

a)

Interpretation:

The major product obtainable from addition of HBr to methylidenecyclohexane is to be predicted.

Concept introduction:

The first step in the addition of HBr with alkenes is the formation of a stable carbocation by the attack of the π electrons of the double bond on the positively polarized hydrogen of HBr eliminating a bromide ion. In the second step the carbocation reacts with the bromide ion to yield the product.

To predict:

The major product obtainable from addition of HBr to methylidenecyclohexane.

Interpretation Introduction

b)

Interpretation:

The major product obtainable from addition of HBr to the octahydronaphthalene is to be predicted.

Concept introduction:

The first step in the addition of HBr with alkenes is the formation of a stable carbocation by the attack of the π electrons of the double bond on the positively polarized hydrogen of HBr eliminating a bromide ion. In the second step the carbocation reacts with the bromide ion to yield the product.

To predict:

The major product obtainable from addition of HBr to octahydronaphthalene.

Interpretation Introduction

c)

Interpretation:

The major product obtainable from addition of HBr to 4-methyl-2-pentene is to be predicted.

Concept introduction:

In electrophilic addition reactions, the first step is the attack of the π electrons of the double bond on the hydrogen of another reactant to yield a carbocation. One of the carbon in C=C gets attached to hydrogen while the other acquires a positive charge. In the second step, the carbocation formed can rearrange to give another more stable carbocation either by a hydride shift (shift of hydrogen atom with its electron pair) or by an alkyl shift (shift of an alkyl group with its electron pair) between neighboring carbons. In the last step the carbocation produced reacts with a negatively charged ion or eliminates a proton to give the product.

To give:

The major product obtainable from addition of HBr to 4-methyl-2-pentene.

Expert Solution & Answer

Trending nowThis is a popular solution!

See solution

Check out sample textbook solution

Answer 4

Question

Chapter 7.SE, Problem 58AP

Interpretation Introduction

a)

Interpretation:

The major product obtainable from addition of HBr to methylidenecyclohexane is to be predicted.

Concept introduction:

The first step in the addition of HBr with alkenes is the formation of a stable carbocation by the attack of the π electrons of the double bond on the positively polarized hydrogen of HBr eliminating a bromide ion. In the second step the carbocation reacts with the bromide ion to yield the product.

To predict:

The major product obtainable from addition of HBr to methylidenecyclohexane.

Interpretation Introduction

b)

Interpretation:

The major product obtainable from addition of HBr to the octahydronaphthalene is to be predicted.

Concept introduction:

The first step in the addition of HBr with alkenes is the formation of a stable carbocation by the attack of the π electrons of the double bond on the positively polarized hydrogen of HBr eliminating a bromide ion. In the second step the carbocation reacts with the bromide ion to yield the product.

To predict:

The major product obtainable from addition of HBr to octahydronaphthalene.

Interpretation Introduction

c)

Interpretation:

The major product obtainable from addition of HBr to 4-methyl-2-pentene is to be predicted.

Concept introduction:

In electrophilic addition reactions, the first step is the attack of the π electrons of the double bond on the hydrogen of another reactant to yield a carbocation. One of the carbon in C=C gets attached to hydrogen while the other acquires a positive charge. In the second step, the carbocation formed can rearrange to give another more stable carbocation either by a hydride shift (shift of hydrogen atom with its electron pair) or by an alkyl shift (shift of an alkyl group with its electron pair) between neighboring carbons. In the last step the carbocation produced reacts with a negatively charged ion or eliminates a proton to give the product.

To give:

The major product obtainable from addition of HBr to 4-methyl-2-pentene.

Expert Solution & Answer

Trending nowThis is a popular solution!

See solution

Check out sample textbook solution

Answer 5

Chapter 7.SE, Problem 58AP

Interpretation Introduction

a)

Interpretation:

The major product obtainable from addition of HBr to methylidenecyclohexane is to be predicted.

Concept introduction:

The first step in the addition of HBr with alkenes is the formation of a stable carbocation by the attack of the π electrons of the double bond on the positively polarized hydrogen of HBr eliminating a bromide ion. In the second step the carbocation reacts with the bromide ion to yield the product.

To predict:

The major product obtainable from addition of HBr to methylidenecyclohexane.

Interpretation Introduction

b)

Interpretation:

The major product obtainable from addition of HBr to the octahydronaphthalene is to be predicted.

Concept introduction:

The first step in the addition of HBr with alkenes is the formation of a stable carbocation by the attack of the π electrons of the double bond on the positively polarized hydrogen of HBr eliminating a bromide ion. In the second step the carbocation reacts with the bromide ion to yield the product.

To predict:

The major product obtainable from addition of HBr to octahydronaphthalene.

Interpretation Introduction

c)

Interpretation:

The major product obtainable from addition of HBr to 4-methyl-2-pentene is to be predicted.

Concept introduction:

In electrophilic addition reactions, the first step is the attack of the π electrons of the double bond on the hydrogen of another reactant to yield a carbocation. One of the carbon in C=C gets attached to hydrogen while the other acquires a positive charge. In the second step, the carbocation formed can rearrange to give another more stable carbocation either by a hydride shift (shift of hydrogen atom with its electron pair) or by an alkyl shift (shift of an alkyl group with its electron pair) between neighboring carbons. In the last step the carbocation produced reacts with a negatively charged ion or eliminates a proton to give the product.

To give:

The major product obtainable from addition of HBr to 4-methyl-2-pentene.

Answer 6

Chapter 7.SE, Problem 58AP

Interpretation Introduction

a)

Interpretation:

The major product obtainable from addition of HBr to methylidenecyclohexane is to be predicted.

Concept introduction:

The first step in the addition of HBr with alkenes is the formation of a stable carbocation by the attack of the π electrons of the double bond on the positively polarized hydrogen of HBr eliminating a bromide ion. In the second step the carbocation reacts with the bromide ion to yield the product.

To predict:

The major product obtainable from addition of HBr to methylidenecyclohexane.

Answer 7

Chapter 7.SE, Problem 58AP

Interpretation Introduction

a)

Interpretation:

The major product obtainable from addition of HBr to methylidenecyclohexane is to be predicted.

Concept introduction:

The first step in the addition of HBr with alkenes is the formation of a stable carbocation by the attack of the π electrons of the double bond on the positively polarized hydrogen of HBr eliminating a bromide ion. In the second step the carbocation reacts with the bromide ion to yield the product.

To predict:

The major product obtainable from addition of HBr to methylidenecyclohexane.

Answer 8

Interpretation Introduction

b)

Interpretation:

The major product obtainable from addition of HBr to the octahydronaphthalene is to be predicted.

Concept introduction:

The first step in the addition of HBr with alkenes is the formation of a stable carbocation by the attack of the π electrons of the double bond on the positively polarized hydrogen of HBr eliminating a bromide ion. In the second step the carbocation reacts with the bromide ion to yield the product.

To predict:

The major product obtainable from addition of HBr to octahydronaphthalene.

Answer 9

Interpretation Introduction

b)

Interpretation:

The major product obtainable from addition of HBr to the octahydronaphthalene is to be predicted.

Concept introduction:

The first step in the addition of HBr with alkenes is the formation of a stable carbocation by the attack of the π electrons of the double bond on the positively polarized hydrogen of HBr eliminating a bromide ion. In the second step the carbocation reacts with the bromide ion to yield the product.

To predict:

The major product obtainable from addition of HBr to octahydronaphthalene.

Answer 10

Interpretation Introduction

c)

Interpretation:

The major product obtainable from addition of HBr to 4-methyl-2-pentene is to be predicted.

Concept introduction:

In electrophilic addition reactions, the first step is the attack of the π electrons of the double bond on the hydrogen of another reactant to yield a carbocation. One of the carbon in C=C gets attached to hydrogen while the other acquires a positive charge. In the second step, the carbocation formed can rearrange to give another more stable carbocation either by a hydride shift (shift of hydrogen atom with its electron pair) or by an alkyl shift (shift of an alkyl group with its electron pair) between neighboring carbons. In the last step the carbocation produced reacts with a negatively charged ion or eliminates a proton to give the product.

To give:

The major product obtainable from addition of HBr to 4-methyl-2-pentene.

Answer 11

Interpretation Introduction

c)

Interpretation:

The major product obtainable from addition of HBr to 4-methyl-2-pentene is to be predicted.

Concept introduction:

In electrophilic addition reactions, the first step is the attack of the π electrons of the double bond on the hydrogen of another reactant to yield a carbocation. One of the carbon in C=C gets attached to hydrogen while the other acquires a positive charge. In the second step, the carbocation formed can rearrange to give another more stable carbocation either by a hydride shift (shift of hydrogen atom with its electron pair) or by an alkyl shift (shift of an alkyl group with its electron pair) between neighboring carbons. In the last step the carbocation produced reacts with a negatively charged ion or eliminates a proton to give the product.

To give:

The major product obtainable from addition of HBr to 4-methyl-2-pentene.

Answer 12

Expert Solution & Answer

Answer 13

Expert Solution & Answer

Answer 14

Trending nowThis is a popular solution!

See solution

Check out sample textbook solution

Answer 15

Trending nowThis is a popular solution!

See solution

Check out sample textbook solution

Answer 16

Trending nowThis is a popular solution!

See solution

Check out sample textbook solution

Answer 17

Trending nowThis is a popular solution!

Answer 18

Trending nowThis is a popular solution!

Answer 19

Trending nowThis is a popular solution!

Answer 20

Trending now

Answer 21

This is a popular solution!

Answer 22

See solution

Check out sample textbook solution

Answer 23

Ch. 7.2 - Calculate the degree of unsaturation in each of...Ch. 7.2 - Prob. 2P Ch. 7.2 - Diazepam, marketed as an antianxiety medication...Ch. 7.3 - Give IUPAC names for the following compounds:Ch. 7.3 - Prob. 5P Ch. 7.3 - Prob. 6P Ch. 7.3 - Prob. 7P Ch. 7.4 - Prob. 8P Ch. 7.4 - Prob. 9P Ch. 7.4 - Prob. 10P

Solution Summary: The author explains the major product obtainable from addition of HBr to methylidenecyclohexane.

Chapter 7 Solutions