The reason behind rate of bimolecular elimination in 1 , 2 , 3 , 4 , 5 , 6 -hexachlorocyclohexane 7000 times slower than it’s any other stereoisomers should be explained. Concept introduction: Experimental evidence for E2 mechanism pathway suggests that it readily occurs if the leaving group with respect to the proton is in anti- orientation in stable chair conformation. For instance, when cis-1-bromo-4- ( 1,1-dimethylethyl ) cyclohexane is treated with strong base it leads to faster bimolecular elimination to afford the corresponding alkene relative to trans-1-bromo-4- ( 1,1-dimethylethyl ) cyclohexane . This is because in the transition state for E2 elimination as illustrated below:

Question

Want to see the full answer?

Answer 1

Question

Chapter 7.7, Problem 7.15TIY

(a)

Interpretation Introduction

Interpretation: The reason behind rate of bimolecular elimination in 1,2,3,4,5,6-hexachlorocyclohexane 7000 times slower than it’s any other stereoisomers should be explained.

Concept introduction: Experimental evidence for E2 mechanism pathway suggests that it readily occurs if the leaving group with respect to the proton is in anti- orientation in stable chair conformation. For instance, when cis-1-bromo-4-(1,1-dimethylethyl)cyclohexane is treated with strong base it leads to faster bimolecular elimination to afford the corresponding alkene relative to trans-1-bromo-4-(1,1-dimethylethyl)cyclohexane . This is because in the transition state for E2 elimination as illustrated below:

(b)

Interpretation Introduction

Interpretation: The formation of only specific elimination product should be explained.

Concept introduction: Experimental evidence for E2 mechanism pathway suggests that it readily occurs if the leaving group with respect to the proton is in anti- orientation in stable chair conformation. For instance, when cis-1-bromo-4-(1,1-dimethylethyl)cyclohexane is treated with strong base it leads to faster bimolecular elimination to afford the corresponding alkene relative to trans-1-bromo-4-(1,1-dimethylethyl)cyclohexane . This is because in the transition state for E2 elimination as illustrated below:

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

In the drawing area below, draw the major products of this organic reaction: If there are no major products, because nothing much will happen to the reactant under these reaction conditions, check the box under the drawing area instead. 1. NaH 2. CH3Br ? Click and drag to start drawing a structure. No reaction. : ☐ N

+ Predict the major product of the following reaction. : ☐ + ☑ ค OH H₂SO4 Click and drag to start drawing a structure.

Consider this organic reaction: ... OH CI Draw the major products of the reaction in the drawing area below. If there won't be any major products, because this reaction won't happen at a significant rate, check the box under the drawing area instead. ☐ No Reaction. Click and drag to start drawing a structure. : а

Answer 2

Question

Chapter 7.7, Problem 7.15TIY

(a)

Interpretation Introduction

Interpretation: The reason behind rate of bimolecular elimination in 1,2,3,4,5,6-hexachlorocyclohexane 7000 times slower than it’s any other stereoisomers should be explained.

Concept introduction: Experimental evidence for E2 mechanism pathway suggests that it readily occurs if the leaving group with respect to the proton is in anti- orientation in stable chair conformation. For instance, when cis-1-bromo-4-(1,1-dimethylethyl)cyclohexane is treated with strong base it leads to faster bimolecular elimination to afford the corresponding alkene relative to trans-1-bromo-4-(1,1-dimethylethyl)cyclohexane . This is because in the transition state for E2 elimination as illustrated below:

(b)

Interpretation Introduction

Interpretation: The formation of only specific elimination product should be explained.

Concept introduction: Experimental evidence for E2 mechanism pathway suggests that it readily occurs if the leaving group with respect to the proton is in anti- orientation in stable chair conformation. For instance, when cis-1-bromo-4-(1,1-dimethylethyl)cyclohexane is treated with strong base it leads to faster bimolecular elimination to afford the corresponding alkene relative to trans-1-bromo-4-(1,1-dimethylethyl)cyclohexane . This is because in the transition state for E2 elimination as illustrated below:

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 3

Question

Chapter 7.7, Problem 7.15TIY

(a)

Interpretation Introduction

Interpretation: The reason behind rate of bimolecular elimination in 1,2,3,4,5,6-hexachlorocyclohexane 7000 times slower than it’s any other stereoisomers should be explained.

Concept introduction: Experimental evidence for E2 mechanism pathway suggests that it readily occurs if the leaving group with respect to the proton is in anti- orientation in stable chair conformation. For instance, when cis-1-bromo-4-(1,1-dimethylethyl)cyclohexane is treated with strong base it leads to faster bimolecular elimination to afford the corresponding alkene relative to trans-1-bromo-4-(1,1-dimethylethyl)cyclohexane . This is because in the transition state for E2 elimination as illustrated below:

(b)

Interpretation Introduction

Interpretation: The formation of only specific elimination product should be explained.

Concept introduction: Experimental evidence for E2 mechanism pathway suggests that it readily occurs if the leaving group with respect to the proton is in anti- orientation in stable chair conformation. For instance, when cis-1-bromo-4-(1,1-dimethylethyl)cyclohexane is treated with strong base it leads to faster bimolecular elimination to afford the corresponding alkene relative to trans-1-bromo-4-(1,1-dimethylethyl)cyclohexane . This is because in the transition state for E2 elimination as illustrated below:

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 4

Question

Chapter 7.7, Problem 7.15TIY

(a)

Interpretation Introduction

Interpretation: The reason behind rate of bimolecular elimination in 1,2,3,4,5,6-hexachlorocyclohexane 7000 times slower than it’s any other stereoisomers should be explained.

Concept introduction: Experimental evidence for E2 mechanism pathway suggests that it readily occurs if the leaving group with respect to the proton is in anti- orientation in stable chair conformation. For instance, when cis-1-bromo-4-(1,1-dimethylethyl)cyclohexane is treated with strong base it leads to faster bimolecular elimination to afford the corresponding alkene relative to trans-1-bromo-4-(1,1-dimethylethyl)cyclohexane . This is because in the transition state for E2 elimination as illustrated below:

(b)

Interpretation Introduction

Interpretation: The formation of only specific elimination product should be explained.

Concept introduction: Experimental evidence for E2 mechanism pathway suggests that it readily occurs if the leaving group with respect to the proton is in anti- orientation in stable chair conformation. For instance, when cis-1-bromo-4-(1,1-dimethylethyl)cyclohexane is treated with strong base it leads to faster bimolecular elimination to afford the corresponding alkene relative to trans-1-bromo-4-(1,1-dimethylethyl)cyclohexane . This is because in the transition state for E2 elimination as illustrated below:

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 5

Chapter 7.7, Problem 7.15TIY

(a)

Interpretation Introduction

Interpretation: The reason behind rate of bimolecular elimination in 1,2,3,4,5,6-hexachlorocyclohexane 7000 times slower than it’s any other stereoisomers should be explained.

Concept introduction: Experimental evidence for E2 mechanism pathway suggests that it readily occurs if the leaving group with respect to the proton is in anti- orientation in stable chair conformation. For instance, when cis-1-bromo-4-(1,1-dimethylethyl)cyclohexane is treated with strong base it leads to faster bimolecular elimination to afford the corresponding alkene relative to trans-1-bromo-4-(1,1-dimethylethyl)cyclohexane . This is because in the transition state for E2 elimination as illustrated below:

(b)

Interpretation Introduction

Interpretation: The formation of only specific elimination product should be explained.

Concept introduction: Experimental evidence for E2 mechanism pathway suggests that it readily occurs if the leaving group with respect to the proton is in anti- orientation in stable chair conformation. For instance, when cis-1-bromo-4-(1,1-dimethylethyl)cyclohexane is treated with strong base it leads to faster bimolecular elimination to afford the corresponding alkene relative to trans-1-bromo-4-(1,1-dimethylethyl)cyclohexane . This is because in the transition state for E2 elimination as illustrated below:

Answer 6

Chapter 7.7, Problem 7.15TIY

(a)

Interpretation Introduction

Interpretation: The reason behind rate of bimolecular elimination in 1,2,3,4,5,6-hexachlorocyclohexane 7000 times slower than it’s any other stereoisomers should be explained.

Concept introduction: Experimental evidence for E2 mechanism pathway suggests that it readily occurs if the leaving group with respect to the proton is in anti- orientation in stable chair conformation. For instance, when cis-1-bromo-4-(1,1-dimethylethyl)cyclohexane is treated with strong base it leads to faster bimolecular elimination to afford the corresponding alkene relative to trans-1-bromo-4-(1,1-dimethylethyl)cyclohexane . This is because in the transition state for E2 elimination as illustrated below:

Answer 7

Chapter 7.7, Problem 7.15TIY

(a)

Interpretation Introduction

Interpretation: The reason behind rate of bimolecular elimination in 1,2,3,4,5,6-hexachlorocyclohexane 7000 times slower than it’s any other stereoisomers should be explained.

Concept introduction: Experimental evidence for E2 mechanism pathway suggests that it readily occurs if the leaving group with respect to the proton is in anti- orientation in stable chair conformation. For instance, when cis-1-bromo-4-(1,1-dimethylethyl)cyclohexane is treated with strong base it leads to faster bimolecular elimination to afford the corresponding alkene relative to trans-1-bromo-4-(1,1-dimethylethyl)cyclohexane . This is because in the transition state for E2 elimination as illustrated below:

Answer 8

(b)

Interpretation Introduction

Interpretation: The formation of only specific elimination product should be explained.

Concept introduction: Experimental evidence for E2 mechanism pathway suggests that it readily occurs if the leaving group with respect to the proton is in anti- orientation in stable chair conformation. For instance, when cis-1-bromo-4-(1,1-dimethylethyl)cyclohexane is treated with strong base it leads to faster bimolecular elimination to afford the corresponding alkene relative to trans-1-bromo-4-(1,1-dimethylethyl)cyclohexane . This is because in the transition state for E2 elimination as illustrated below:

Answer 9

(b)

Interpretation Introduction

Interpretation: The formation of only specific elimination product should be explained.

Concept introduction: Experimental evidence for E2 mechanism pathway suggests that it readily occurs if the leaving group with respect to the proton is in anti- orientation in stable chair conformation. For instance, when cis-1-bromo-4-(1,1-dimethylethyl)cyclohexane is treated with strong base it leads to faster bimolecular elimination to afford the corresponding alkene relative to trans-1-bromo-4-(1,1-dimethylethyl)cyclohexane . This is because in the transition state for E2 elimination as illustrated below:

Answer 10

Expert Solution & Answer

Answer 11

Expert Solution & Answer

Answer 12

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 13

Ch. 7.1 - Prob. 7.1E Ch. 7.2 - Prob. 7.2E Ch. 7.3 - Prob. 7.3E Ch. 7.3 - Prob. 7.5TIY Ch. 7.4 - Prob. 7.7TIY Ch. 7.5 - Prob. 7.9TIY Ch. 7.6 - Prob. 7.10E Ch. 7.7 - Prob. 7.11E Ch. 7.7 - Prob. 7.12E Ch. 7.7 - Prob. 7.13E

Solution Summary: The author explains the reason behind the rate of bimolecular elimination in 1,2,3,4,5,6-hexachlorocyclexane.

Want to see the full answer?

Chapter 7 Solutions