ORGANIC CHEMISTRY (LL)-PACKAGE
ORGANIC CHEMISTRY (LL)-PACKAGE
8th Edition
ISBN: 9781319316389
Author: VOLLHARDT
Publisher: MAC HIGHER
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Chapter 7.7, Problem 7.13E
Interpretation Introduction

Interpretation: The reason behind specific product formed in below reaction should be written.

  ORGANIC CHEMISTRY (LL)-PACKAGE, Chapter 7.7, Problem 7.13E

Concept introduction: Carbocation formation is relatively slower than acid-base reactions. Carbocations generated from alkyl halides have two fates; they can be either trapped by nucleophiles to give substitution product or may deprotonated to yield small amount of alkene. Stronger the base more is the probability of elimination over substitution over elimination. Further, if still higher concentration is employed reaction proceeds via bimolecular elimination. On the other hand, weak base waits until the carbocation is formed and the type of elimination with relatively weak base is two-step elimination or E1 .

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Transmitance 3. Which one of the following compounds corresponds to this IR spectrum? Point out the absorption band(s) that helped you decide. OH H3C OH H₂C CH3 H3C CH3 H3C INFRARED SPECTRUM 0.8- 0.6 0.4- 0.2 3000 2000 1000 Wavenumber (cm-1) 4. Consider this compound: H3C On the structure above, label the different types of H's as A, B, C, etc. In table form, list the labeled signals, and for each one state the number of hydrogens, their shifts, and the splitting you would observe for these hydrogens in the ¹H NMR spectrum. Label # of hydrogens splitting Shift (2)
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