Chapter 7.3, Problem 102AYU

To determine

To graph: The mentioned trigonometric function $f\left(x\right)=2\sin x$ and $g\left(x\right)=-2\sin x+2$ on the same Cartesian plane where $x\in \left[0,2\pi \right]$ .

Explanation of Solution

Given information:

The mentioned trigonometric function $f\left(x\right)=2\sin x$ and $g\left(x\right)=-2\sin x+2$ .

Graph:

The graph provided below is the mentioned trigonometric function $f\left(x\right)=2\sin x$ and $g\left(x\right)=-2\sin x+2$ . The graph is plotted in the x axis and y axis real number line.

Here we can see in the mentioned graph below that the function $g\left(x\right)=-2\sin x+2$ is plotted by blue coloured curve and function $f\left(x\right)=2\sin x$ is plotted by red coloured curve .The graph is plotted in the interval $x\in \left[0,2\pi \right]$ .

  

Interpretation:

The general process of graph along with the description of their traces is provided below.

Since we know that the graph of sin x is symmetric about origin.

Therefore on the interval of $x\in \left[0,2\pi \right]$ the graph $g\left(x\right)=-2\sin x+2$ and $f\left(x\right)=2\sin x$ will be on positive side of x axis

Now for the graph $g\left(x\right)=-2\sin x+2$ if we multiply any negative sign constant to sin x then the graph will shrink from its original position and if we add some constant to the same function then the graph will oscillates in it period and will expand from its original position.

And for the graph $f\left(x\right)=2\sin x$ if we multiply any constant to sin x then the graph will shrink from its original position and expand to take new position as shown in the graph mentioned above.

Thus the graph of function $f\left(x\right)=2\sin x$ is shown as mentioned above in the graph and the constant $g\left(x\right)=-2\sin x+2$ is as plotted in the mentioned point in the x axis

Therefore the graph of the function $f\left(x\right)=2\sin x$ and $g\left(x\right)=-2\sin x+2$ is as shown above in the same Cartesian plane.