
Concept explainers
To calculate: The exact value of expression csc[tan−1(−2)] .

Answer to Problem 30AYU
The exact value is y1 −√52 .
Explanation of Solution
Given information:
csc[tan−1(−2)] .
Formula used:
Equation y=tan−1x means tany=x .
Theorem :- For any angle θ , in standard position, let P=(x,y) be the point on the terminal side of θ , that is on the circle x2+y2=r2 . Then
sinθ=yrcosθ=xrtanθ=yx,x≠0cosecθ=ry,y≠0secθ=rx,x≠0cotθ=xy,y≠0 .
Calculation:
Consider ,
csc[tan−1(−2)]
Let
θ=tan−1(−2)tanθ=(−2)
where −π2<θ<π2 .
Since tanθ<0 , it follows −π2<θ≤0 .
This implies θ lies in quadrant IV.
Now,
tanθ=yx=−21
=y=−2;x=1
Using equation of circle we have,
=x2+y2=r2=(12)+(−22)=r2=1+4=r2=5=r2=r=±√5
Thus we have,
=x=1;y=−2;r=√5 .
Now,
csc[tan−1(−2)]=cscθ=−√52 ( where cscry )
Hence , the exact value of csc[sin−1(−2)] is −√52 .
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