47. H(x) = (2x + 3)4 48. H(x) = (1 + x²) * 3 50. 1 (х) — Vi- 52. H(x) = |2r + 3| 49. Н(х) — V#+1 51. H(x) = |2x + 1|

Algebra: Structure And Method, Book 1
(REV)00th Edition
ISBN:9780395977224
Author:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Publisher:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Chapter4: Polynomials
Section4.6: Multiplying Polynomials
Problem 47WE
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In Problems 47–52, find functions f and g so that f ∘ g = H.

47. H(x) = (2x + 3)4
48. H(x) = (1 + x²) *
3
50. 1 (х) — Vi-
52. H(x) = |2r + 3|
49. Н(х) — V#+1
51. H(x) = |2x + 1|
Transcribed Image Text:47. H(x) = (2x + 3)4 48. H(x) = (1 + x²) * 3 50. 1 (х) — Vi- 52. H(x) = |2r + 3| 49. Н(х) — V#+1 51. H(x) = |2x + 1|
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