
(a)
Interpretation:
The structural formula of 2,3-Dimethylcyclobutane should be drawn.
Concept Introduction:
Compounds consist of carbon and hydrogen is known as hydrocarbons. Saturated hydrocarbon is known as
The compounds in which series of atoms are connected to form a ring is known as cyclic compound whereas the compounds which are open chain compounds and their atoms doesn't form a ring is known as acyclic compounds. The general molecular formula of cyclic alkane is
Rules of drawing structures of cycloalkanes are:
- First identify the base name, and then draw the cyclic ring of carbon atoms according to the base name.
- After that according to the given position of the substituents, locate them on carbon atoms (replacement of hydrogen atom occurs).
(b)
Interpretation:
The structural formula of 2-Methyl-2-butene should be drawn.
Concept Introduction:
Compounds consist of carbon and hydrogen is known as hydrocarbons.
Rules of drawing structures of
- First identify the base name, and then draw the straight chain of carbon atoms according to the base name.
- After that according to the given position of the substituents, locate them on carbon atoms (replacement of hydrogen atom occurs).
(c)
Interpretation:
The structural formula of 2-Methyl-1,3-butadiene should be drawn.
Concept Introduction:
Compounds consist of carbon and hydrogen is known as hydrocarbons. Unsaturated hydrocarbon having one or more double bond is known as alkene having general molecular formula
Rules of drawing structures of alkenes are:
- First identify the base name, and then draw the straight chain of carbon atoms according to the base name.
- After that according to the given position of the substituents, locate them on carbon atoms (replacement of hydrogen atom occurs).
(d)
Interpretation:
The structural formula of 2,3-Dimethyl-3-ethylhexane should be drawn.
Concept Introduction:
Compounds consist of carbon and hydrogen is known as hydrocarbons. Saturated hydrocarbon is known as alkane having general molecular formula
Rules of drawing structures of alkanes are:
- First identify the base name, and then draw the straight chain of carbon atoms according to the base name.
- After that according to the given position of the substituents, locate them on carbon atoms (replacement of hydrogen atom occurs).
(e)
Interpretation:
The structural formula of 4,5-diethyloctane should be drawn.
Concept Introduction:
Compounds consist of carbon and hydrogen is known as hydrocarbons. Saturated hydrocarbon is known as alkane having general molecular formula
Rules of drawing structures of alkanes are:
- First identify the base name, and then draw the straight chain of carbon atoms according to the base name.
- After that according to the given position of the substituents, locate them on carbon atoms (replacement of hydrogen atom occurs).
(f)
Interpretation:
The structural formula of Cyclooctene should be drawn.
Concept Introduction:
Compounds consist of carbon and hydrogen is known as hydrocarbons. Unsaturated hydrocarbon with one or more double bond is known as alkene having general molecular formula
The compounds in which series of atoms are connected to form a ring is known as cyclic compound whereas the compounds which are open chain compounds and their atoms doesn't form a ring is known as acyclic compounds. The general molecular formula of cyclic alkene is
Where, m represents number of double bonds.
Rules of drawing structures of cycloalkenes are:
- First identify the base name, and then draw the cyclic ring of carbon atoms according to the base name.
- After that according to the given position of the substituents, locate them on carbon atoms (replacement of hydrogen atom occurs).
(g)
Interpretation:
The structural formula of Propadiene should be drawn.
Concept Introduction:
Compounds consist of carbon and hydrogen is known as hydrocarbons. Unsaturated hydrocarbon having one or more double bond is known as alkene having general molecular formula
Rules of drawing structures of alkenes are:
- First identify the base name, and then draw the straight chain of carbon atoms according to the base name.
- After that according to the given position of the substituents, locate them on carbon atoms (replacement of hydrogen atom occurs).
(h)
Interpretation:
The structural formula of 2-pentyne should be drawn.
Concept Introduction:
Compounds consist of carbon and hydrogen is known as hydrocarbons. Unsaturated hydrocarbon with one or more triple bond is known as alkyne having general molecular formula
Rules of drawing structures of
- First identify the base name, and then draw the straight chain of carbon atoms according to the base name.
- After that according to the given position of the substituents, locate them on carbon atoms (replacement of hydrogen atom occurs).

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Chapter 7 Solutions
Principles of Modern Chemistry
- Using reaction free energy to predict equilibrium composition Consider the following equilibrium: N2O4 (g) 2NO2 (g) AG⁰ = 5.4 kJ Now suppose a reaction vessel is filled with 1.68 atm of dinitrogen tetroxide (N204) at 148. °C. Answer the following questions about this system: rise Under these conditions, will the pressure of N2O4 tend to rise or fall? x10 fall Is it possible to reverse this tendency by adding NO2? In other words, if you said the pressure of N2O4 will tend to rise, can that be changed to a tendency to fall by adding NO2? Similarly, if you said the pressure of N2O4 will tend to fall, can that be changed to a tendency to rise by adding NO2? If you said the tendency can be reversed in the second question, calculate the minimum pressure of NO 2 needed to reverse it. Round your answer to 2 significant digits. yes no 0.42 atm ☑ 5 0/5 ? مله Ararrow_forwardHomework 13 (Ch17) Question 4 of 4 (1 point) | Question Attempt: 2 of 2 ✓ 1 ✓ 2 = 3 4 Time Remaining: 4:25:54 Using the thermodynamic information in the ALEKS Data tab, calculate the standard reaction free energy of the following chemical reaction: 2CH3OH (g)+302 (g) → 2CO2 (g) + 4H₂O (g) Round your answer to zero decimal places. ☐ kJ x10 ☐ Subm Check 2020 Hill LLC. All Rights Reserved. Terms of Use | Privacy Cearrow_forwardIdentifying the major species in weak acid or weak base equilibria Your answer is incorrect. • Row 2: Your answer is incorrect. • Row 3: Your answer is incorrect. • Row 6: Your answer is incorrect. 0/5 The preparations of two aqueous solutions are described in the table below. For each solution, write the chemical formulas of the major species present at equilibrium. You can leave out water itself. Write the chemical formulas of the species that will act as acids in the 'acids' row, the formulas of the species that will act as bases in the 'bases' row, and the formulas of the species that will act as neither acids nor bases in the 'other' row. You will find it useful to keep in mind that HF is a weak acid. acids: HF 0.1 mol of NaOH is added to 1.0 L of a 0.7M HF solution. bases: 0.13 mol of HCl is added to 1.0 L of a solution that is 1.0M in both HF and KF. Exponent other: F acids: HF bases: F other: K 1 0,0,... ? 000 18 Ararrow_forward
- Using reaction free energy to predict equilibrium composition Consider the following equilibrium: 2NOCI (g) 2NO (g) + Cl2 (g) AGº =41. kJ Now suppose a reaction vessel is filled with 4.50 atm of nitrosyl chloride (NOCI) and 6.38 atm of chlorine (C12) at 212. °C. Answer the following questions about this system: ? rise Under these conditions, will the pressure of NOCI tend to rise or fall? x10 fall Is it possible to reverse this tendency by adding NO? In other words, if you said the pressure of NOCI will tend to rise, can that be changed to a tendency to fall by adding NO? Similarly, if you said the pressure of NOCI will tend to fall, can that be changed to a tendency to rise by adding NO? yes no If you said the tendency can be reversed in the second question, calculate the minimum pressure of NO needed to reverse it. Round your answer to 2 significant digits. 0.035 atm ✓ G 00. 18 Ararrow_forwardHighlight each glycosidic bond in the molecule below. Then answer the questions in the table under the drawing area. HO- HO- -0 OH OH HO NG HO- HO- OH OH OH OH NG OHarrow_forward€ + Suppose the molecule in the drawing area below were reacted with H₂ over a platinum catalyst. Edit the molecule to show what would happen to it. That is, turn it into the product of the reaction. Also, write the name of the product molecule under the drawing area. Name: ☐ H C=0 X H- OH HO- H HO- -H CH₂OH ×arrow_forward
- Draw the Haworth projection of the disaccharide made by joining D-glucose and D-mannose with a ẞ(1-4) glycosidic bond. If the disaccharide has more than one anomer, you can draw any of them. Click and drag to start drawing a structure. Xarrow_forwardEpoxides can be opened in aqueous acid or aqueous base to produce diols (molecules with two OH groups). In this question, you'll explore the mechanism of epoxide opening in aqueous acid. 2nd attempt Be sure to show all four bonds at stereocenters using hash and wedge lines. 0 0 Draw curved arrows to show how the epoxide reacts with hydronium ion. 100 +1: 1st attempt Feedback Be sure to show all four bonds at stereocenters using hash and wedge lines. See Periodic Table See Hint H A 5 F F Hr See Periodic Table See Hintarrow_forward03 Question (1 point) For the reaction below, draw both of the major organic products. Be sure to consider stereochemistry. > 1. CH₂CH₂MgBr 2. H₂O 3rd attempt Draw all four bonds at chiral centers. Draw all stereoisomers formed. Draw the structures here. e 130 AN H See Periodic Table See Hint P C Brarrow_forward
- You may wish to address the following issues in your response if they are pertinent to the reaction(s) you propose to employ:1) Chemoselectivity (why this functional group and not another?) 2) Regioselectivity (why here and not there?) 3) Stereoselectivity (why this stereoisomer?) 4) Changes in oxidation state. Please make it in detail and draw it out too in what step what happens. Thank you for helping me!arrow_forward1) Chemoselectivity (why this functional group and not another?) 2) Regioselectivity (why here and not there?) 3) Stereoselectivity (why this stereoisomer?) 4) Changes in oxidation state. Everything in detail and draw out and write it.arrow_forwardCalculating the pH at equivalence of a titration 3/5 Izabella A chemist titrates 120.0 mL of a 0.7191M dimethylamine ((CH3)2NH) solution with 0.5501 M HBr solution at 25 °C. Calculate the pH at equivalence. The pk of dimethylamine is 3.27. Round your answer to 2 decimal places. Note for advanced students: you may assume the total volume of the solution equals the initial volume plus the volume of HBr solution added. pH = ☐ ✓ 18 Ar Boarrow_forward
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