Concept explainers
(a)
Interpretation:
The balanced chemical equation should be written for the production of butyl acetate from butanol and acetic acid.
Concept Introduction:
Compounds consist of carbon and hydrogen is known as hydrocarbons. Hydrocarbons are classified as saturated hydrocarbon and unsaturated hydrocarbon. Saturated hydrocarbons are those hydrocarbons in which carbon-carbon single bond is present as carbon is linked with four atoms.
The balanced chemical equation is defined as the equation in which number of different atoms of elements on reactant side is similar to that of product side.
The formulas which contains different symbols for different atoms and connected by a line that denotes
(b)
Interpretation:
The balanced chemical equation should be written for the conversion of ammonium acetate to acetamide and water.
Concept Introduction:
Compounds consist of carbon and hydrogen is known as hydrocarbons. Hydrocarbons are classified as saturated hydrocarbon and unsaturated hydrocarbon. Saturated hydrocarbons are those hydrocarbons in which carbon-carbon single bond is present as carbon is linked with four atoms. Unsaturated hydrocarbons are those hydrocarbons in which carbon-carbon multiple bonds are present that is double and triple bond.
The balanced chemical equation is defined as the equation in which number of different atoms of elements on reactant side is similar to that of product side.
The formulas which contains different symbols for different atoms and connected by a line that denotes chemical bond is known as structural formulas. One line represents single bond, two lines represent double bond and three lines represent triple bond.
(c)
Interpretation:
The balanced chemical equation should be written for the dehydrogenation of 1-propanol.
Concept Introduction:
Compounds consist of carbon and hydrogen is known as hydrocarbons. Hydrocarbons are classified as saturated hydrocarbon and unsaturated hydrocarbon. Saturated hydrocarbons are those hydrocarbons in which carbon-carbon single bond is present as carbon is linked with four atoms. Unsaturated hydrocarbons are those hydrocarbons in which carbon-carbon multiple bonds are present that is double and triple bond.
The balanced chemical equation is defined as the equation in which number of different atoms of elements on reactant side is similar to that of product side.
The formulas which contains different symbols for different atoms and connected by a line that denotes chemical bond is known as structural formulas. One line represents single bond, two lines represent double bond and three lines represent triple bond.
(d)
Interpretation:
The balanced chemical equation should be written for the complete combustion of heptane.
Concept Introduction:
Compounds consist of carbon and hydrogen is known as hydrocarbons. Hydrocarbons are classified as saturated hydrocarbon and unsaturated hydrocarbon. Saturated hydrocarbons are those hydrocarbons in which carbon-carbon single bond is present as carbon is linked with four atoms. Unsaturated hydrocarbons are those hydrocarbons in which carbon-carbon multiple bonds are present that is double and triple bond.
The balanced chemical equation is defined as the equation in which number of different atoms of elements on reactant side is similar to that of product side.
The formulas which contains different symbols for different atoms and connected by a line that denotes chemical bond is known as structural formulas. One line represents single bond, two lines represent double bond and three lines represent triple bond.
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Chapter 7 Solutions
Principles of Modern Chemistry
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- Liquid chromatography has been used to track the concentration of remdesivir (a broad-spectrum antiviral drug, structure shown at right) in COVID patients undergoing experimental treatments. Intensity The authors provide the following details regarding standard solutions preparation: HN CN HO OH NH2 Remdesivir (RDV) stock solution (5000 µg/mL) was prepared by dissolving RDV drug powder using the mixture of DMSO: MeOH (30:70 v/v). The RDV working standard solutions for calibration and quality controls were prepared using methanol in concentrations of 100, 10, 1, 0.1, 0.01 µg/mL. 1, 2.5, 5, 7.5, 10, 25, 50, 75, 100, 250, 500, 1000, and 5000 ng/mL sample solutions were prepared freshly by spiking calibration standard solutions into the blank human plasma samples for method calibration. a) What type of calibration method is being described? Why do you think the authors chose this method as opposed to another? b) Based on the details provided in part a, describe an appropriate method blank…arrow_forwardRecent advancements in liquid chromatography include the development of ultrahigh pressure liquid chromatography (UHPLC) and an increased use of capillary columns that had previously only been used with gas chromatography. Both of these advances have made the development of portable LC systems possible. For example, Axcend Corp. makes a portable system that uses a capillary column with an internal diameter of 150-μm-that is packed with 1.7-um stationary phase particles. In contrast, a traditional LC column has a 4.6 mm internal diameter and utilizes 5-um stationary phase particles. a) Explain one advantage that is afforded by the use of a capillary column in liquid chromatographic separation. Explain one disadvantage of capillary columns. b) Explain how the use of smaller stationary phase particles can improve the resolution of a separation. Include any relevant equations that support your explanation. c) A scientist at Rowan University is using the Axcend LC to conduct analyses of F…arrow_forwardThis paper describes the use of fullerene molecules, also known as buckyballs, as a stationary phase for liquid chromatography. The performance of the fullerene-modified stationary phase (FMS) is compared to that of a more common C18 stationary phase and to two other carbon-based stationary phases, PGC and COZ. A. 10A OM B. - Figure 1. Idealized drawing of the cross-section of a pore inside a silica particle, showing the relative densities of aminopropylsilyl (red/green) and fullerene (blue) groups: (A) full cross- section; (B) detailed view of covalent bonding of fullerene to the silica surface. Surface densities of silyl and fullerene groups were inferred from elemental composition results obtained at each stage of the synthesis (see Table 1). Absorbance (mAU, 220 nm) 700 600 500 400 300 200 100 a. Define selectivity, a, with words and an equation. b. Explain how the choice of stationary phase affects selectivity. c. Calculate the resolution of the nitrobenzene and toluene peaks in…arrow_forward
- Normalized Intensity (a. u.) 0.5 1.0 A 3D-printed GC column (shown below) was created for use with "micro" gas chromatography applications. To prove its utility, it was used to separate a mixture of alkanes (C9-C18, C22, C24). For the separation shown below, the column temperature was ramped from 40 °C to 250 °C at a rate of 30 °C per minute. (a) 9 10 = 1 mm 12 13 15 22 0.0 0 100 200 300 400 Time (sec) a) What detector would you use for this analysis? Justify your selection. b) Explain how the chromatogram would change if the separation was run isothermally. c) Explain how the chromatogram would change if the temperature ramp were increased to 50 °C per minute.arrow_forwardDevise a synthesis of each compound from the indicated starting material. You may also use any organic compounds with one or two carbons and any needed inorganic reagents. a. Brarrow_forwardPlease help me with #2b & #3 using the data.arrow_forward
- Heparin is used as an anti-coagulant. A risk of heparin use is thrombocytopenia, or low platelet count. This risk is minimized with the use of low molecular weight heparins (LMWH), therefore it is desirable to separate LMWH from higher molecular weight heparins. The method of choice to do this is molecular exclusion chromatography. Below is a chromatogram from a molecular exclusion chromatographic run. Peaks ranging from A to J are clearly distinguishable. The heparin mixture that was analyzed had anywhere from 6 to 30 repeat units of monomer (where the heparin with 30 repeat units would be roughly five times the size of the heparin with six repeat units). a. Which letter most likely represents the peak with 6 repeat units given these heparin polymers were separated with molecular exclusion chromatography? b. Explain your reasoning describing the mechanism of retention in molecular exclusion chromatography. 100 80 60 60 Relative Abundance 40 40 E GH 20 20 B A 36 38 40 42 44 46 48 50 50…arrow_forwardHELP NOW PLEASE ! URGENT!arrow_forwardHELP NOW PLEASE ! URGENT!arrow_forward
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