Principles of Modern Chemistry
Principles of Modern Chemistry
8th Edition
ISBN: 9781305079113
Author: David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Publisher: Cengage Learning
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Chapter 7, Problem 22P

(a)

Interpretation Introduction

Interpretation:

The chemical equation should be written for the synthesis of vinyl acetate from easily available inorganic and petrochemicals starting materials.

Concept Introduction:

The chemicals which are derived from the natural gas and crude oil are known as petrochemicals and inorganic materials don’t contain carbon and hydrogen atoms.

The balanced chemical equation is defined as the equation in which number of different atoms of elements on reactant side is similar to that of product side.

(b)

Interpretation Introduction

Interpretation:

The chemical equation should be written for the synthesis of Formamide from easily available inorganic and petrochemicals starting materials.

Concept Introduction:

The chemicals which are derived from the natural gas and crude oil are known as petrochemicals and inorganic materials don’t contain carbon and hydrogen atoms.

The balanced chemical equation is defined as the equation in which number of different atoms of elements on reactant side is similar to that of product side.

(c)

Interpretation Introduction

Interpretation:

The chemical equation should be written for the synthesis of 1,2-difluoroethane from easily available inorganic and petrochemicals starting materials

Concept Introduction:

The chemicals which are derived from the natural gas and crude oil are known as petrochemicals and inorganic materials don’t contain carbon and hydrogen atoms.

The balanced chemical equation is defined as the equation in which number of different atoms of elements on reactant side is similar to that of product side.

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Relative Intensity Part VI. consider the multi-step reaction below for compounds A, B, and C. These compounds were subjected to mass spectrometric analysis and the following spectra for A, B, and C was obtained. Draw the structure of B and C and match all three compounds to the correct spectra. Relative Intensity Relative Intensity 100 HS-NJ-0547 80 60 31 20 S1 84 M+ absent 10 30 40 50 60 70 80 90 100 100- MS2016-05353CM 80- 60 40 20 135 137 S2 164 166 0-m 25 50 75 100 125 150 m/z 60 100 MS-NJ-09-43 40 20 20 80 45 S3 25 50 75 100 125 150 175 m/z
Part II. Given two isomers: 2-methylpentane (A) and 2,2-dimethyl butane (B) answer the following: (a) match structures of isomers given their mass spectra below (spectra A and spectra B) (b) Draw the fragments given the following prominent peaks from each spectrum: Spectra A m/2 =43 and 1/2-57 spectra B m/2 = 43 (c) why is 1/2=57 peak in spectrum A more intense compared to the same peak in spectrum B. Relative abundance Relative abundance 100 A 50 29 29 0 10 -0 -0 100 B 50 720 30 41 43 57 71 4-0 40 50 60 70 m/z 43 57 8-0 m/z = 86 M 90 100 71 m/z = 86 M -O 0 10 20 30 40 50 60 70 80 -88 m/z 90 100
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