Materials Science And Engineering Properties
1st Edition
ISBN: 9781111988609
Author: Charles Gilmore
Publisher: Cengage Learning
expand_more
expand_more
format_list_bulleted
Question
Chapter 7, Problem 41CQ
To determine
Whether the density, crystallinity, yield strength, and elastic modulus can be increased or decreased by side branches on polymer.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
The modulus of elasticity are slightly higher for ceramic
materials, Polymers have modulus values that are smaller than
both metals and ceramics.
16) Which of the following mechanical
properties can be measured / calculated
from this tensile stress-strain graph of a
generic metal alloy? (pick all that apply)
a. Poisson's ratio
b. Elastic modulus
C.
Shear modulus
d. Flexural modulus
e. Fracture toughness
17) Interstitial sites in a FCC lattice are called
a.
Rhombohedral and cubic
b. Cubic and hexagonal
C.
Monoclinic and triclinic
Stress (MPa)
2000
MPa
2000
1000
1000
0.000
0.005 0.010
0.015
Strain
0.000
0.020
0.040
Strain
0.060
0.080
d. Tetrahedral and octahedral
e. Heterogeneous and homogeneous
18) Traditional photovoltaics rely on which structural feature to separate charge carriers?
a. The p-n junction
b. The grain boundaries
C.
The twin boundaries
d. The electron-hole pair
e. The band gap
19) The process by which lithium ions move in to and out of graphite in a lithium-ion battery is
called
a.
Intercalation
b. Stacking
C.
Precipitation
d. Phase combination
e.
lonization
20) A polymer obtained by the polymerization of two types…
How can some high strength polymers such as Kevlar polymer have higher strength than some metals?
Chapter 7 Solutions
Materials Science And Engineering Properties
Ch. 7 - Prob. 1CQCh. 7 - Prob. 2CQCh. 7 - Prob. 3CQCh. 7 - Prob. 4CQCh. 7 - Prob. 5CQCh. 7 - Prob. 6CQCh. 7 - Prob. 7CQCh. 7 - Prob. 8CQCh. 7 - Prob. 9CQCh. 7 - Prob. 10CQ
Ch. 7 - Prob. 11CQCh. 7 - Prob. 12CQCh. 7 - Prob. 13CQCh. 7 - Prob. 14CQCh. 7 - Prob. 15CQCh. 7 - Prob. 16CQCh. 7 - Prob. 17CQCh. 7 - Prob. 18CQCh. 7 - Prob. 19CQCh. 7 - Prob. 20CQCh. 7 - Prob. 21CQCh. 7 - Prob. 22CQCh. 7 - Prob. 23CQCh. 7 - Prob. 24CQCh. 7 - Prob. 25CQCh. 7 - Prob. 26CQCh. 7 - Prob. 27CQCh. 7 - Prob. 28CQCh. 7 - Prob. 29CQCh. 7 - Prob. 30CQCh. 7 - Prob. 31CQCh. 7 - Prob. 32CQCh. 7 - Prob. 33CQCh. 7 - Prob. 34CQCh. 7 - Prob. 35CQCh. 7 - Prob. 36CQCh. 7 - Prob. 37CQCh. 7 - Prob. 38CQCh. 7 - Prob. 39CQCh. 7 - Prob. 40CQCh. 7 - Prob. 41CQCh. 7 - Prob. 42CQCh. 7 - Prob. 43CQCh. 7 - Prob. 44CQCh. 7 - Prob. 45CQCh. 7 - Prob. 46CQCh. 7 - Prob. 47CQCh. 7 - Prob. 48CQCh. 7 - Prob. 49CQCh. 7 - Prob. 50CQCh. 7 - Prob. 51CQCh. 7 - Prob. 52CQCh. 7 - Prob. 1DRQCh. 7 - Prob. 2DRQCh. 7 - Prob. 3DRQCh. 7 - Prob. 4DRQCh. 7 - Prob. 5DRQCh. 7 - Prob. 6DRQCh. 7 - Prob. 7DRQCh. 7 - Prob. 8DRQCh. 7 - Prob. 1ETSQCh. 7 - Prob. 2ETSQCh. 7 - Prob. 3ETSQCh. 7 - Prob. 4ETSQCh. 7 - Prob. 5ETSQCh. 7 - Prob. 6ETSQCh. 7 - Prob. 7ETSQCh. 7 - Prob. 8ETSQCh. 7 - Prob. 9ETSQCh. 7 - Prob. 7.1PCh. 7 - Prob. 7.2PCh. 7 - Prob. 7.3PCh. 7 - Prob. 7.4PCh. 7 - Prob. 7.5PCh. 7 - Prob. 7.6PCh. 7 - Prob. 7.7PCh. 7 - Prob. 7.8PCh. 7 - Prob. 7.9PCh. 7 - Prob. 7.10PCh. 7 - Prob. 7.11PCh. 7 - Prob. 7.13P
Knowledge Booster
Similar questions
- This is a mechanical property of engineering materials that exhibits a slow deformation under long term sustained loads.arrow_forwardDraw a tensile stress-strain curve for a typical semi-crystalline polymer such as LLDPE, and define the three main regions on the curve.arrow_forward3.What is a dislocation? List five more microscopic defects in bulk materials. Which of the following properties are most sensitive to dislocation structures in materials? a. Young's modulus b. Yield strength c. Conductivity d. Transparencyarrow_forward
- Material A is known as a high strength material and Material B has high toughness. Explain the difference between properties of Materials A and B.arrow_forwardA laminated [0/90/0/90]s graphite/epoxy beam is 1 mm thick, is 20 mm wide, and has 0.125 mm thick plies. The lamina properties are E1 = 180 GPa, E2 = 10 GPa, ν12 = 0.28, G12 = 7 GPa Xt = 1700 MPa, Xc = 1400 MPa, Yt = 40 MPa, Yc = 230 MPa (a) Determine the flexural modulus of the beam (b) How could the flexural modulus be improved without changing the ply materials, the number of plies, or the ply orientations? (c) Using the Maximum Stress Criterion for each ply, determine the magnitude of the maximum allowable bending moment that the beam can withstand. Which ply fails first?arrow_forward10)Which of the following statements are correct regarding the Adhesive bonding process? a. Bonding relies on the attractive forces between the molecules at the surface of the adhesive and that of the surfaces to be joined. b. The smaller molecules provide better adhesion. c. The liquid adhesives do not require any form of curing. d. The curing temperature is always maintained at over 500°C.arrow_forward
- Explain how dislocations have paradoxically rationalized why metals can be bothmechanically weak and strong. How have dislocations helped to explain work hardening of metals.arrow_forwardThe stress in an elastic material is: A Inversely proportional to the force acting B Inversely proportional to the materials yield strength C Proportional to the displacement D Inversely proportional to the strainarrow_forwardMake a comparison between polymers and ceramics based on (a) mechanical properties and (b) on molecular structures under the effect of heating to temperatures.arrow_forward
- Given your understanding of what initiates and controls failure in materials, which of the following will increase the failure strength or lifetime of a test piece or component and why? a. Decreasing the difference between the maximum and minimum stress values, as this effects the stress concentration factor b. Decreasing the temperature below the brittle-ductile transition temperature, to make it harder C. Polishing to reduce surface defects Od. Increasing its volume, to give a larger cross sectional area Oe. Increasing the grain size so there are less grain boundaries to initiate failurearrow_forwardAn aluminum alloy [E = 70 GPa; v = 0.33; a = 23.0×10-6/°C] bar is subjected to a tensile load P. The bar has a depth of d = 260 mm, a cross-sectional area of A = 14720 mm2, and a length of L = 5.5 m. The initial longitudinal normal strain in the bar is zero. After load P is applied and the temperature of the bar has been increased by AT = 46°C, the longitudinal normal strain is found to be 1680 µɛ. % D Calculate the change in bar depth d after the load P has been applied and the temperature has been increased. L P Answer: Ad = i mmarrow_forwardThe deformation per unit length is called O(A) Tensile stress O(B) Compressive stress OCC) Shear stress O(D) Strainarrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Materials Science And Engineering PropertiesCivil EngineeringISBN:9781111988609Author:Charles GilmorePublisher:Cengage Learning
Materials Science And Engineering Properties
Civil Engineering
ISBN:9781111988609
Author:Charles Gilmore
Publisher:Cengage Learning