Materials Science And Engineering Properties
1st Edition
ISBN: 9781111988609
Author: Charles Gilmore
Publisher: Cengage Learning
expand_more
expand_more
format_list_bulleted
Question
Chapter 7, Problem 7.11P
To determine
The activation enthalpy for precipitate formation.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
Using the isothermal transformation diagram for a 0.45 wt% C steel alloy (Figure 10.40), determine the final microstructure (in terms of just the microconstituents present) AND approximate percentages of the microconstituents that form in a small specimen that has been subjected to the following time-temperature treatments. In each case assume that the specimen begins at 845°C (1550°F), and that it has been held at this temperature long enough to have achieved a complete and homogeneous austenitic structure. (a) Rapidly cool to 250°C (480°F), hold for 10^3 s, then quench to room temperature.
(b) Rapidly cool to 700°C (1290°F), hold for 30 s, then quench to room temperature.
(c) Rapidly cool to 700°C (1290°F), hold at this temperature for 10^5 s, then quench to room temperature.
(d) Rapidly cool to 400°C (750°F), hold for 500 s, then quench to room temperature.
View Policies
Current Attempt in Progress
Using the Animated Figure 10.40, the isothermal transformation diagram for a 0.45 wt% C steel alloy, specify the nature of the final
microstructure (in terms of the microconstituents present) of a small specimen that has been subjected to the following
temperature treatments. In each case assume that the specimen begins at 845 °C and that it has been held at this temperature long
enough to have achieved a complete and homogeneous austenitic structure.
a) Rapidly cool to 700 degrees C, hold for 100,000 s, then quench to room temperature.
b) Rapidly cool to 450 degrees C, hold for 10 s, then quench to room temperature.
proeutectoid ferrite + pearlite
proeutectoid ferrite + martensite
proeutectoid ferrite + pearlite + martensite
eT
proeutectoid ferrite + pearlite + bainite + martensite
all spheroidite
Save
all bainite
Attempts: 0 of 5 used
Submit Answer
all martensite
bainite + martensite
Q.1. For hypereutectoid plain carbon steel (select %C content yourself), determine the phases that
are present, the compositions of these phases, and the percentages or fractions of the phases. Make
schematic sketches of the microstructure that would be observed for conditions of very slow
cooling at the following temperatures:
a) Just above the austenite transformation temperature
b) The austenite transformation temperature 10°C
c) The eutectoid transformation temperature +10°C
d) The eutectoid transformation temperature 10°C
Chapter 7 Solutions
Materials Science And Engineering Properties
Ch. 7 - Prob. 1CQCh. 7 - Prob. 2CQCh. 7 - Prob. 3CQCh. 7 - Prob. 4CQCh. 7 - Prob. 5CQCh. 7 - Prob. 6CQCh. 7 - Prob. 7CQCh. 7 - Prob. 8CQCh. 7 - Prob. 9CQCh. 7 - Prob. 10CQ
Ch. 7 - Prob. 11CQCh. 7 - Prob. 12CQCh. 7 - Prob. 13CQCh. 7 - Prob. 14CQCh. 7 - Prob. 15CQCh. 7 - Prob. 16CQCh. 7 - Prob. 17CQCh. 7 - Prob. 18CQCh. 7 - Prob. 19CQCh. 7 - Prob. 20CQCh. 7 - Prob. 21CQCh. 7 - Prob. 22CQCh. 7 - Prob. 23CQCh. 7 - Prob. 24CQCh. 7 - Prob. 25CQCh. 7 - Prob. 26CQCh. 7 - Prob. 27CQCh. 7 - Prob. 28CQCh. 7 - Prob. 29CQCh. 7 - Prob. 30CQCh. 7 - Prob. 31CQCh. 7 - Prob. 32CQCh. 7 - Prob. 33CQCh. 7 - Prob. 34CQCh. 7 - Prob. 35CQCh. 7 - Prob. 36CQCh. 7 - Prob. 37CQCh. 7 - Prob. 38CQCh. 7 - Prob. 39CQCh. 7 - Prob. 40CQCh. 7 - Prob. 41CQCh. 7 - Prob. 42CQCh. 7 - Prob. 43CQCh. 7 - Prob. 44CQCh. 7 - Prob. 45CQCh. 7 - Prob. 46CQCh. 7 - Prob. 47CQCh. 7 - Prob. 48CQCh. 7 - Prob. 49CQCh. 7 - Prob. 50CQCh. 7 - Prob. 51CQCh. 7 - Prob. 52CQCh. 7 - Prob. 1DRQCh. 7 - Prob. 2DRQCh. 7 - Prob. 3DRQCh. 7 - Prob. 4DRQCh. 7 - Prob. 5DRQCh. 7 - Prob. 6DRQCh. 7 - Prob. 7DRQCh. 7 - Prob. 8DRQCh. 7 - Prob. 1ETSQCh. 7 - Prob. 2ETSQCh. 7 - Prob. 3ETSQCh. 7 - Prob. 4ETSQCh. 7 - Prob. 5ETSQCh. 7 - Prob. 6ETSQCh. 7 - Prob. 7ETSQCh. 7 - Prob. 8ETSQCh. 7 - Prob. 9ETSQCh. 7 - Prob. 7.1PCh. 7 - Prob. 7.2PCh. 7 - Prob. 7.3PCh. 7 - Prob. 7.4PCh. 7 - Prob. 7.5PCh. 7 - Prob. 7.6PCh. 7 - Prob. 7.7PCh. 7 - Prob. 7.8PCh. 7 - Prob. 7.9PCh. 7 - Prob. 7.10PCh. 7 - Prob. 7.11PCh. 7 - Prob. 7.13P
Knowledge Booster
Similar questions
- Describe the basic properties of Halloysite.arrow_forwardA 100.0-mL sample of spring water was treated to convert any iron present to Fe+2. Addition of 25.00-mL of 0.015102 N K2Cr2O7 resulted in the reaction. The excess K2Cr2O7 (294 g/mol) was back-titrated with 8.53 mL of 0.00949 N Fe+2 solution. The concentration of Fe+2 (56 g/mol) in the sample in parts per million is ___________.arrow_forwardWhat are the various parameters that affect the viscosity of a polymer melt, and how do they affect its propertiesarrow_forward
- The following information is given for cadmium at 1atm: boiling point = 765 °C Hvap(765 °C) = 100 kJ/mol melting point = 321 °C Hfus(321 °C) = 6.11 kJ/mol specific heat solid= 0.230 J/g°C specific heat liquid = 0.264 J/g°C __________kJ are required to melt a 31.0 g sample of solid cadmium, Cd, at its normal melting point.arrow_forwardCompare the difference in hardenability of plain carbon steels given below. Hardenability is the strengthening of steels by the process of quenching + tempering. Chemical compositions ( wt % ) C Mn P S Fe Steel 1 0.2 0.45 0.04 0.05 99.26 Steel 2 0.4 0.75 0.04 0.05 98.76 Steel 3 0.6 0.75 0.04 0.05 98.56arrow_forwardDescribe the basic properties of Montmorillonite.arrow_forward
- Q.4. Give a reason for the following facts: 1- Ceramics fail after only about 0.1% strain under tensile test. 2- Porosity is an inherent defects in ceramics. 3- Ceramics carbides consider ideal choice for ceramic abrasives. 4- Orthoclase has the advantage over other types of feldspar.arrow_forward34 If the following diagram represents the sintering of the ceramic MgO, what could the curves x and y refer to? increase in property X 1000 1200 1600 sintering temperature (°C) (A) = grain size; y porosity (B) x grain size; y = strength O(C) x porosity; y-grain size 1400 O (D) x strength; y grain size 1800arrow_forwardWhat would you expect if you have a 6061 aluminum alloy bar, heat it for 1 hour in the oven forming a single phase, then severely temper it in water and then heat it at 150 ° for 6 hours. ? a) ductility is increased b) increases yield stress c) hardness is reduced d) the material is over-aged and the yield stress is reducedarrow_forward
- subject: Material Engineering Using the given sheet for the Ni-Ti Phase diagram, how many phase fields appear in the diagram and write down the weight fraction of gamma phase for an alloy containing 43% wt of Ti at 1000 Carrow_forwardFor alloys of two hypothetical metals A and B, there exist an a, A-rich phase and a ß, B-rich phase. From the mass fractions of both phases for two different alloys (given below), which are at the same temperature, determine the composition of the phase boundary (or solubility limit) for the following: Fraction Fraction Alloy Composition a Phase B Phase 60 wt% A - 40 wt% B 0.59 0.41 30 wt% A - 70 wt% B 0.13 0.87 (a) a phase wt% A (b) B phase wt% Aarrow_forwardWhen the exponential trend line of iron concentration vs time is y=4.2 exp(-0.24x) x is time in min and y is concentration of phen iron complex solution.arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Materials Science And Engineering PropertiesCivil EngineeringISBN:9781111988609Author:Charles GilmorePublisher:Cengage Learning
Materials Science And Engineering Properties
Civil Engineering
ISBN:9781111988609
Author:Charles Gilmore
Publisher:Cengage Learning