Chapter 6.8, Problem 26SGR

To determine

To calculate; $p(-2)$ and $p(x+h)$ for each of the given functions.

Answer to Problem 26SGR

Solution: $p(-2)=14$

                  $p(x+h)=3x^2+6xh+3h^2-x-h$

Explanation of Solution

Find $p(x)$ by replacing the variable $x$ with the given value.

  $\begin{array}{l}$ p(-2)=3{(-2)}^2-(-2)$p(-2)=3(4)-(-2)\\ p(-2)=14\end{array}$

  $\begin{array}{l}$ p(x+h)=3{(x+h)}^2-(x+h)$p(x+h)=3(x^2+2xh+h^2)-x-h\\ p(x+h)=3x^2+6xh+3h^2-x-h\end{array}$