Concept explainers
State the possible number of real zeros, negative real zeros, and imaginary zeros of each function.
Answer to Problem 30PPS
Explanation of Solution
Given information:
The given equation is
The given equation has degree 3, therefore, it has 3 zeros. To find the positive real zeros, count the number of changes in sign for the coefficients of
There are 2 sign changes, so there are 2 or 0 positive real zeros.
There are 2 sign changes, so there are 2 or 0 negative real zero.
The table of possible combinations of real and imaginary zeros.
Chapter 6 Solutions
Algebra 2
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