Chapter 6, Problem 11MCQ

To determine

Find the solution of the function at the given value.

Answer to Problem 11MCQ

The solution of the function at the given value is $0$ .

Explanation of Solution

Given:

The given function is $p\left(x\right)=\frac{2}{3}{x}^3+\frac{1}{3}{x}^2-5x$ and the given value is $p\left(-3\right)$ .

Calculation:

The original function is

  $p\left(x\right)=\frac{2}{3}{x}^3+\frac{1}{3}{x}^2-5x$

Replace the $x$ in $p\left(x\right)$ with $-3$ .

  $\begin{array}{l}p\left(-3\right)=\frac{2}{3}{\left(-3\right)}^3+\frac{1}{3}{\left(-3\right)}^2-5\left(-3\right)\\ =\frac{2}{3}\cdot \left(-27\right)+\frac{1}{3}\cdot 9+15\\ =-18+3+15\\ =0\end{array}$

Hence the solution of the function at the given value is $0$ .