Chapter 6.8, Problem 1STP

To determine

To calculate: The simplified form of : $\left(5n^2+11n-6\right)-\left(2n^2-5\right)$ .

Answer to Problem 1STP

The simplified form of $\left(5n^2+11n-6\right)-\left(2n^2-5\right)$ is $3n^2+11n-1$ .

Explanation of Solution

Given information:

The statement “ $\left(5n^2+11n-6\right)-\left(2n^2-5\right)$ .”

  $\begin{array}{l}A3n^2+11n-11\text{ C }7n^2+11n-11\\ B\text{ 3}{n}^2+11n-1\text{ D }7n^2+11n-1\end{array}$

Formula used:

When two or more functions are in subtraction then subtract the coefficient of $x^2$ to $x^2$ and coefficient of $x$ to $x$ and constant to constant ,

Consider the provided statement “ $\left(5n^2+11n-6\right)-\left(2n^2-5\right)$ .”

Recall that When two or more functions are in subtraction then subtract the coefficient of $x^2$ to $x^2$ and coefficient of $x$ to $x$ and constant to constant ,

So, the given expression can be simplified as,

  $\left(5n^2+11n-6\right)-\left(2n^2-5\right)$

Observe to solve the expression.

  $\begin{array}{l}\left(5n^2+11n-6\right)-\left(2n^2-5\right)\\ 5n^2+11n-6-2n^2+5\\ 5n^2-2n^2+11n-6+5\\ 3n^2+11n-1\end{array}$ .

Since, $3n^2+11n-1$ cannot be simplified further,

Hence, the simplified form of $\left(5n^2+11n-6\right)-\left(2n^2-5\right)$ is $3n^2+11n-1$ .