Chapter 6.3, Problem 25PPS

To determine

To find:

The value of $p\left(-6\right),p\left(3\right)$

Answer to Problem 25PPS

The value of, $p\left(-6\right)=-156,p\left(3\right)=78$

Explanation of Solution

Given:

  $p\left(x\right)=2x^3+6x^2-10x$

Concept:

Using the given value of the function

Calculation:

The function

  $p\left(x\right)=2x^3+6x^2-10x\mathrm{.........}\left(1\right)$

Putting the value $x=-6,3$ in equation (1)

  $\begin{array}{l}p\left(x\right)=2x^3+6x^2-10x\\ p\left(-6\right)=2{\left(-6\right)}^3+6{\left(-6\right)}^2-10\left(-6\right)\\ p\left(-6\right)=-432+216+60\\ p\left(-6\right)=-156\\ p\left(3\right)=2{\left(3\right)}^3+6{\left(3\right)}^2-10\left(3\right)\\ p\left(3\right)=54+54-30\\ p\left(3\right)=78\end{array}$