Chapter 6.2, Problem 68S

To determine

To find: the value of $g\left(-8\right)$

Answer to Problem 68S

The Values of $g\left(-8\right)=-64$

Explanation of Solution

Given Information:

  $\begin{array}{l}f\left(x\right)=4x+3\\ g\left(x\right)=-x^2\\ h\left(x\right)=-2x^2-2x+4\end{array}$

Point at which the value is calculated is $g\left(-8\right)$ .

The values at $g\left(-8\right)$ are calculated as:

  $\begin{array}{l}g\left(x\right)=-x^2\\ g\left(-8\right)=-{\left(-8\right)}^2\\ g\left(-8\right)=-64\end{array}$

Thus the values are is $g\left(-8\right)=-64$