
Concept explainers
In Problems 17-40, graph each function. Be sure to label key points and show at least two cycles. Use the graph to determine the domain and the range of each function.

To find: Domain and range.
Answer to Problem 35AYU
Solution:
Domain is .
Range .
Explanation of Solution
Given:
Calculation:
The graph .
By the graph we determine that the domain of this function is the set of all real numbers where cosecant is defined, which excludes points where vertical asymptotes occur. Since this happens when . Therefore the domain is . To determine the range we take note of the value of , which will scale the underlying reciprocal sine function amplitude to 1. The given function will not enter into the space of the cosine (apart from its maxima and minima). The range . This agrees with the graph provided.
Therefore the,
Domain is .
Range .
Chapter 6 Solutions
Precalculus
Additional Math Textbook Solutions
University Calculus: Early Transcendentals (4th Edition)
Algebra and Trigonometry (6th Edition)
Basic Business Statistics, Student Value Edition
College Algebra with Modeling & Visualization (5th Edition)
Elementary Statistics (13th Edition)
Pre-Algebra Student Edition
- A 20 foot ladder rests on level ground; its head (top) is against a vertical wall. The bottom of the ladder begins by being 12 feet from the wall but begins moving away at the rate of 0.1 feet per second. At what rate is the top of the ladder slipping down the wall? You may use a calculator.arrow_forwardExplain the focus and reasons for establishment of 12.4.1(root test) and 12.4.2(ratio test)arrow_forwarduse Integration by Parts to derive 12.6.1arrow_forward
- Explain the relationship between 12.3.6, (case A of 12.3.6) and 12.3.7arrow_forwardExplain the key points and reasons for the establishment of 12.3.2(integral Test)arrow_forwardUse 12.4.2 to determine whether the infinite series on the right side of equation 12.6.5, 12.6.6 and 12.6.7 converges for every real number x.arrow_forward
- use Corollary 12.6.2 and 12.6.3 to derive 12.6.4,12.6.5, 12.6.6 and 12.6.7arrow_forwardExplain the focus and reasons for establishment of 12.5.1(lim(n->infinite) and sigma of k=0 to n)arrow_forwardExplain the focus and reasons for establishment of 12.5.3 about alternating series. and explain the reason why (sigma k=1 to infinite)(-1)k+1/k = 1/1 - 1/2 + 1/3 - 1/4 + .... converges.arrow_forward
- Calculus: Early TranscendentalsCalculusISBN:9781285741550Author:James StewartPublisher:Cengage LearningThomas' Calculus (14th Edition)CalculusISBN:9780134438986Author:Joel R. Hass, Christopher E. Heil, Maurice D. WeirPublisher:PEARSONCalculus: Early Transcendentals (3rd Edition)CalculusISBN:9780134763644Author:William L. Briggs, Lyle Cochran, Bernard Gillett, Eric SchulzPublisher:PEARSON
- Calculus: Early TranscendentalsCalculusISBN:9781319050740Author:Jon Rogawski, Colin Adams, Robert FranzosaPublisher:W. H. FreemanCalculus: Early Transcendental FunctionsCalculusISBN:9781337552516Author:Ron Larson, Bruce H. EdwardsPublisher:Cengage Learning





