Concept explainers
(a)
Interpretation:
Organic product that is formed in the given reaction has to be classified as primary amine, secondary amine, tertiary amine or quaternary salt.
Concept Introduction:
Alkylation reaction is a reaction in which the transfer of alkyl group from one molecule to another molecule takes place. While considering
Amine is an organic derivative. If in ammonia one or more alkyl, cycloalkyl, or aryl groups are substituted instead of hydrogen atom then it is known as amine. Depending on the number of substitution the amines are classified as primary, secondary or tertiary amine. Primary amine is the one in which only one hydrogen atom in ammonia is replaced by a hydrocarbon group. Secondary amine is the one in which only two hydrogen atoms in ammonia is replaced by a hydrocarbon group. Tertiary amine is the one in which all three hydrogen atoms in ammonia is replaced by a hydrocarbon group. The generalized structural formula for all the amines is,
Quaternary ammonium salt is the one that has four carbon atoms attached to the nitrogen atom. This is formed by the reaction of tertiary amine with alkyl halide in presence of a strong base.
(a)
Answer to Problem 6.63EP
Organic product is a primary amine.
Explanation of Solution
Given reaction is,
The reactants given in the above reaction are ammonia, propyl chloride. Sodium hydroxide is a reagent that is used for basic condition in this case. As the reaction between ammonia and propyl chloride gives propylamine as the product, this is an alkylation reaction. The complete reaction can be given as,
The organic product formed is propylamine. Considering the nitrogen atom in propylamine, it is bonded to one carbon atom and two hydrogen atoms. Hence, it is a primary amine.
The organic product formed in the given reaction is classified.
(b)
Interpretation:
Organic product that is formed in the given reaction has to be classified as primary amine, secondary amine, tertiary amine or quaternary salt.
Concept Introduction:
Alkylation reaction is a reaction in which the transfer of alkyl group from one molecule to another molecule takes place. While considering amines, the alkylating agent that is used is alkyl halides. Alkylation is done under basic conditions. The general equations for amines alkylation process is,
Amine is an organic derivative. If in ammonia one or more alkyl, cycloalkyl, or aryl groups are substituted instead of hydrogen atom then it is known as amine. Depending on the number of substitution the amines are classified as primary, secondary or tertiary amine. Primary amine is the one in which only one hydrogen atom in ammonia is replaced by a hydrocarbon group. Secondary amine is the one in which only two hydrogen atoms in ammonia is replaced by a hydrocarbon group. Tertiary amine is the one in which all three hydrogen atoms in ammonia is replaced by a hydrocarbon group. The generalized structural formula for all the amines is,
Quaternary ammonium salt is the one that has four carbon atoms attached to the nitrogen atom. This is formed by the reaction of tertiary amine with alkyl halide in presence of a strong base.
(b)
Answer to Problem 6.63EP
Organic product is a tertiary amine.
Explanation of Solution
Given reaction is,
The reactants given in the above reaction are isopropylmethylamine, methyl bromide. Sodium hydroxide is a reagent that is used for basic condition in this case. As the reaction between isopropylmethylamine and methyl bromide gives isopropyldimethylamine as the product, this is an alkylation reaction. The complete reaction can be given as,
The organic product that is formed has a nitrogen atom that is bonded to three carbon atoms. Hence, it is a tertiary amine.
The organic product formed in the given reaction is classified.
(c)
Interpretation:
Organic product that is formed in the given reaction has to be classified as primary amine, secondary amine, tertiary amine or quaternary salt.
Concept Introduction:
Alkylation reaction is a reaction in which the transfer of alkyl group from one molecule to another molecule takes place. While considering amines, the alkylating agent that is used is alkyl halides. Alkylation is done under basic conditions. The general equations for amines alkylation process is,
Amine is an organic derivative. If in ammonia one or more alkyl, cycloalkyl, or aryl groups are substituted instead of hydrogen atom then it is known as amine. Depending on the number of substitution the amines are classified as primary, secondary or tertiary amine. Primary amine is the one in which only one hydrogen atom in ammonia is replaced by a hydrocarbon group. Secondary amine is the one in which only two hydrogen atoms in ammonia is replaced by a hydrocarbon group. Tertiary amine is the one in which all three hydrogen atoms in ammonia is replaced by a hydrocarbon group. The generalized structural formula for all the amines is,
Quaternary ammonium salt is the one that has four carbon atoms attached to the nitrogen atom. This is formed by the reaction of tertiary amine with alkyl halide in presence of a strong base.
(c)
Answer to Problem 6.63EP
Organic product is a secondary amine.
Explanation of Solution
Given reaction is,
The reactants given in the above reaction are ethylamine, ethyl chloride. Sodium hydroxide is a reagent that is used for basic condition in this case. As the reaction between ethylamine and ethyl chloride gives diethylamine as the product, this is an alkylation reaction. The complete reaction can be given as,
The organic product obtained has a nitrogen atom that is bonded to two carbon atoms and one hydrogen atom. Hence, it is a secondary amine.
The organic product formed in the given reaction is classified.
(d)
Interpretation:
Organic product that is formed in the given reaction has to be classified as primary amine, secondary amine, tertiary amine or quaternary salt.
Concept Introduction:
Alkylation reaction is a reaction in which the transfer of alkyl group from one molecule to another molecule takes place. While considering amines, the alkylating agent that is used is alkyl halides. Alkylation is done under basic conditions. The general equations for amines alkylation process is,
Amine is an organic derivative. If in ammonia one or more alkyl, cycloalkyl, or aryl groups are substituted instead of hydrogen atom then it is known as amine. Depending on the number of substitution the amines are classified as primary, secondary or tertiary amine. Primary amine is the one in which only one hydrogen atom in ammonia is replaced by a hydrocarbon group. Secondary amine is the one in which only two hydrogen atoms in ammonia is replaced by a hydrocarbon group. Tertiary amine is the one in which all three hydrogen atoms in ammonia is replaced by a hydrocarbon group. The generalized structural formula for all the amines is,
Quaternary ammonium salt is the one that has four carbon atoms attached to the nitrogen atom. This is formed by the reaction of tertiary amine with alkyl halide in presence of a strong base.
(d)
Answer to Problem 6.63EP
Organic product is a primary amine.
Explanation of Solution
Given reaction is,
The reactants given in the above reaction are ammonia, tert-butyl bromide. Sodium hydroxide is a reagent that is used for basic condition in this case. As the reaction between ammonia and tert-butyl bromide gives tert-butylamine as the product, this is an alkylation reaction. The complete reaction can be shown as,
The organic product formed has a nitrogen atom that is bonded to one carbon atom and two hydrogen atoms. Hence, it is a primary amine.
The organic product formed in the given reaction is classified.
Want to see more full solutions like this?
Chapter 6 Solutions
Organic And Biological Chemistry
- Zeroth Order Reaction In a certain experiment the decomposition of hydrogen iodide on finely divided gold is zeroth order with respect to HI. 2HI(g) Au H2(g) + 12(9) Rate = -d[HI]/dt k = 2.00x104 mol L-1 s-1 If the experiment has an initial HI concentration of 0.460 mol/L, what is the concentration of HI after 28.0 minutes? 1 pts Submit Answer Tries 0/5 How long will it take for all of the HI to decompose? 1 pts Submit Answer Tries 0/5 What is the rate of formation of H2 16.0 minutes after the reaction is initiated? 1 pts Submit Answer Tries 0/5arrow_forwardangelarodriguezmunoz149@gmail.com Hi i need help with this question i am not sure what the right answers are.arrow_forwardPlease correct answer and don't used hand raitingarrow_forward
- Don't used hand raitingarrow_forwardDon't used Ai solutionarrow_forwardSaved v Question: I've done both of the graphs and generated an equation from excel, I just need help explaining A-B. Below is just the information I used to get the graphs obtain the graph please help. Prepare two graphs, the first with the percent transmission on the vertical axis and concentration on the horizontal axis and the second with absorption on the vertical axis and concentration on the horizontal axis. Solution # Unknown Concentration (mol/L) Transmittance Absorption 9.88x101 635 0.17 1.98x101 47% 0.33 2.95x101 31% 0.51 3.95x10 21% 0.68 4.94x10 14% 24% 0.85 0.62 A.) Give an equation that relates either the % transmission or the absorption to the concentration. Explain how you arrived at your equation. B.) What is the relationship between the percent transmission and the absorption? C.) Determine the concentration of the ironlll) salicylate in the unknown directly from the graph and from the best fit trend-line (least squares analysis) of the graph that yielded a straight…arrow_forward
- General, Organic, and Biological ChemistryChemistryISBN:9781285853918Author:H. Stephen StokerPublisher:Cengage LearningOrganic And Biological ChemistryChemistryISBN:9781305081079Author:STOKER, H. Stephen (howard Stephen)Publisher:Cengage Learning,Introduction to General, Organic and BiochemistryChemistryISBN:9781285869759Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar TorresPublisher:Cengage Learning
- Chemistry for Today: General, Organic, and Bioche...ChemistryISBN:9781305960060Author:Spencer L. Seager, Michael R. Slabaugh, Maren S. HansenPublisher:Cengage Learning