
(a)
Interpretation:
Structural formula of the salt that is produced by reaction between ethylamine and
Concept Introduction:
Neutralization reaction is the one that takes place between an acid and a base to give salt as product. As
(b)
Interpretation:
Structural formula of the salt that is produced by reaction between cyclopentylamine and
Concept Introduction:
Neutralization reaction is the one that takes place between an acid and a base to give salt as product. As amines are bases due to the amino group in it, the reaction with inorganic acid or carboxylic acid gives salt as product. The salt formed is an amine salt. Proton is donated from the acid to the nitrogen atom which acts as a proton acceptor. In simple words, it can be said that in an amine‑acid reaction, the acid loses a hydrogen ion and amine gains a hydrogen ion.
(c)
Interpretation:
Structural formula of the salt that is produced by reaction between isopropylamine and
Concept Introduction:
Neutralization reaction is the one that takes place between an acid and a base to give salt as product. As amines are bases due to the amino group in it, the reaction with inorganic acid or carboxylic acid gives salt as product. The salt formed is an amine salt. Proton is donated from the acid to the nitrogen atom which acts as a proton acceptor. In simple words, it can be said that in an amine‑acid reaction, the acid loses a hydrogen ion and amine gains a hydrogen ion.
(d)
Interpretation:
Structural formula of the salt that is produced by reaction between ethylethylamine and
Concept Introduction:
Neutralization reaction is the one that takes place between an acid and a base to give salt as product. As amines are bases due to the amino group in it, the reaction with inorganic acid or carboxylic acid gives salt as product. The salt formed is an amine salt. Proton is donated from the acid to the nitrogen atom which acts as a proton acceptor. In simple words, it can be said that in an amine‑acid reaction, the acid loses a hydrogen ion and amine gains a hydrogen ion.

Want to see the full answer?
Check out a sample textbook solution
Chapter 6 Solutions
Organic And Biological Chemistry
- Can I get helpp drawing my arrowsarrow_forwardWhich of the m/z values corresponds to the base peak in the mass spectrum shown? 100 80 A. 45 B. 44 C. 29 D. 15 Intensity 20 0 10 20 30 40 B- m/z -8 50 E. 30 Which of the m/z values correspond to the molecular ion for the compound shown? A. 18 B. 82 OH C. 100 D. 102 E. 103arrow_forwardCan someone help me with drawing my arrows.arrow_forward
- I'm having trouble with converting lewis diagrams into VSEPR diagrams. I currently have this example of C2BrCl3 which I want to turn into a lewis structure, but I'm not sure what steps I need to do in order to do so. I have the table written down, however, there's two central atoms so what would I do? There seems to be 4 electron domains on the carbon atom and no lone pairs so it would seem like this shape would be tetrahedral. Here's what I have now. Thanks!arrow_forwardWe discussed the solid phase resin using in peptide synthesis. Provide a mechanism, for its formation. DRAW THE MECHANISM.arrow_forwardPlease help. Every time I've asked an expert in the past, it's been wrong :(arrow_forward
- General, Organic, and Biological ChemistryChemistryISBN:9781285853918Author:H. Stephen StokerPublisher:Cengage LearningOrganic And Biological ChemistryChemistryISBN:9781305081079Author:STOKER, H. Stephen (howard Stephen)Publisher:Cengage Learning,Chemistry for Today: General, Organic, and Bioche...ChemistryISBN:9781305960060Author:Spencer L. Seager, Michael R. Slabaugh, Maren S. HansenPublisher:Cengage Learning
- Organic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage Learning



