Explanation The required reaction is given below. N H 4 H S ( s ) ⇌ N H 3 ( g ) + H 2 S ( g ) , K c = 1.6 × 10 − 4 The expression for equilibrium constant for the above reaction can be written as shown below, K c = [ N H 3 ] [ H 2 S ] Given that, the number of moles of ammonia initially present in the reaction vessel of volume 2.00 L is 0.400 m o l . The concentration of ammonia can be calculated as given below. [ N H 3 ] = m o l e s v o l u m e = 0.400 m o l 2.00 L = 0 . 2 0 0 M An equilibrium table can be set up as given below. C o m p o s i t i o n ( M ) N H 3 H 2 S I n i t i a l c o n c e n t r a t i o n 0.200 0 C h a n g e i n c o n c e n t r a t i o n + x + x E q u i l i b r i u m c o n c e n t r a t i o n 0.200 + x x Now, these values in the fourth row can be inserted in the equilibrium constant expression as shown below

ACHIEVE/CHEMICAL PRINCIPLES ACCESS 1TERM

7th Edition

ISBN: 9781319399849

Author: ATKINS

Publisher: MAC HIGHER

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Question

Chapter 5, Problem 5I.15E

Interpretation Introduction

Interpretation:

The equilibrium molar concentrations of NH3 and H2S in a reaction vessel of volume 2.0 L have to be calculated. The reaction is given below.

NH4HS(s)⇌NH3(g)+H2S(g), Kc=1.6×10−4

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Chapter 5, Problem 5I.14E

Chapter 5, Problem 5I.16E

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Chapter 5 Solutions

ACHIEVE/CHEMICAL PRINCIPLES ACCESS 1TERM

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Knowledge Booster

The equilibrium molar concentrations of N H 3 a n d H 2 S in a reaction vessel of volume 2.0 L have to be calculated. The reaction is given below. N H 4 H S ( s ) ⇌ N H 3 ( g ) + H 2 S ( g ) , K c = 1.6 × 10 − 4

Solution Summary: The author explains how the equilibrium molar concentrations of NH_3and12S in a reaction vessel of volume 2.0 L have to

Interpretation:

The equilibrium molar concentrations of NH3 and H2S in a reaction vessel of volume 2.0 L have to be calculated. The reaction is given below.

NH4HS(s)⇌NH3(g)+H2S(g), Kc=1.6×10−4

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Chapter 5 Solutions

The equilibrium molar concentrations of N H 3 a n d H 2 S in a reaction vessel of volume 2.0 L have to be calculated. The reaction is given below. N H 4 H S ( s ) ⇌ N H 3 ( g ) + H 2 S ( g ) , K c = 1.6 × 10 − 4

Solution Summary: The author explains how the equilibrium molar concentrations of NH_3and12S in a reaction vessel of volume 2.0 L have to

Interpretation: The equilibrium molar concentrations of NH3 and H2S in a reaction vessel of volume 2.0 L have to be calculated. The reaction is given below. NH4HS(s)⇌NH3(g)+H2S(g), Kc=1.6×10−4

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Chapter 5 Solutions

Interpretation:

The equilibrium molar concentrations of NH3 and H2S in a reaction vessel of volume 2.0 L have to be calculated. The reaction is given below.

NH4HS(s)⇌NH3(g)+H2S(g), Kc=1.6×10−4