Chapter 5, Problem 5.30E

Interpretation Introduction

Interpretation:

When $0.10g$ of insulin is dissolved in $0.200L$ of water, the osmotic pressure is $2.30Torr$ at $\text{20}{}^{\text{o}}\text{C}$. Molar mass of insulin has to be calculated.

Concept introduction:

Molar mass can be calculated by using following formula,

  $\begin{array}{l}M=\frac{m\text{RT}}{\text{V}\times \text{Π}}\\ \\ \text{Where,}\\ \text{Π}\text{-}\text{Osmatic}\text{pressure}\\ \text{V}\text{-}\text{Volume}\\ \text{n}\text{=}\text{moles}\\ \text{T}\text{-}\text{Temperature}\\ \text{R}\text{-}\text{Gas}\text{constant}\end{array}$