Physics for Scientists and Engineers with Modern Physics, Technology Update
Physics for Scientists and Engineers with Modern Physics, Technology Update
9th Edition
ISBN: 9781305401969
Author: SERWAY, Raymond A.; Jewett, John W.
Publisher: Cengage Learning
Question
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Chapter 41, Problem 12P

(a)

To determine

The lowest possible energy of proton.

(b)

To determine

The lowest possible energy for an electron.

(c)

To determine

To compare the results in the above parts.

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Show that the units 1 v2/Q = 1 W, as implied by the equation P = V²/R. Starting with the equation P = V²/R, we can get an expression for a watt in terms of voltage and resistance. The units for voltage, V, are equivalent to [? v2 v2 A, are equivalent to J/C ✓ X . Therefore, 1 = 1 = 1 A V1 J/s Ω V-A X = 1 W. . The units for resistance, Q, are equivalent to ? The units for current,
Please solve and answer the question correctly please. Thank you!!
Please solve and answer the question correctly please. Thank you!!

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Physics for Scientists and Engineers with Modern Physics, Technology Update

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