Concept explainers
(a)
Interpretation:
The Lewis structure of the given polyatomic ion has to be drawn.
Concept introduction:
In a Lewis structure, lines are represented for the bonding between atoms of a molecule and the dots for the lone pairs of electrons that may exist in the molecule.
Valence electrons of carbon, chlorine and oxygen are 4, 7 and 6 respectively.
(b)
Interpretation:
The Lewis structure of the given polyatomic ion has to be drawn.
Concept introduction:
In a Lewis structure, lines are represented for the bonding between atoms of a molecule and the dots for the lone pairs of electrons that may exist in the molecule.
Valence electrons of sulfur and oxygen are 6 and 6 respectively.
(c)
Interpretation:
The Lewis structure of the given polyatomic ion has to be drawn.
Concept introduction:
In a Lewis structure, lines are represented for the bonding between atoms of a molecule and the dots for the lone pairs of electrons that may exist in the molecule.
Valence electrons of carbon, nitrogen and sulfur are 4, 5 and 6 respectively.
(d)
Interpretation:
The Lewis structure of the given polyatomic ion has to be drawn.
Concept introduction:
In a Lewis structure, lines are represented for the bonding between atoms of a molecule and the dots for the lone pairs of electrons that may exist in the molecule.
Valence electrons of phosphorus and oxygen are 3 and 6 respectively.
(e)
Interpretation:
The Lewis structure of the given polyatomic ion has to be drawn.
Concept introduction:
In a Lewis structure, lines are represented for the bonding between atoms of a molecule and the dots for the lone pairs of electrons that may exist in the molecule.
Valence electrons of chlorine and oxygen are 7 and 6 respectively.
Want to see the full answer?
Check out a sample textbook solutionChapter 4 Solutions
Fundamentals of General, Organic, and Biological Chemistry (8th Edition)
- Consider nitrous acid, HNO2 (HONO).(a) Write a Lewis structure.(b) What are the electron pair and molecular geometries of the internal oxygen and nitrogen atoms in the HNO2 molecule?(c) What is the hybridization on the internal oxygen and nitrogen atoms in HNO2?arrow_forwardDraw a structure for the compound, C3H5Br, that fits the following 1H NMR data: δ 2.32 (3H, singlet) δ 5.35 (1H, broad singlet) δ 5.54 (1H, broad singlet)arrow_forwardCompound P was discovered by a scientist. Compound P is a dipeptide, optically active and has the molecular formula C„H14N2O3. Compound P is formed when compound Q and compound R joined together by condensation reaction. While, monomers S and T are formed by modifying the compounds Q and R. Polymer U is formed by the condensation reaction of monomers S and T. Draw the possible structural formulae of compounds P, Q, R, S, T and U. Label the peptide bond(s) for compound P. Draw the possible structural formulae for repeating unit of polymer U. Please state the number of functional groups present in compound P.arrow_forward
- a) what two types of bonds are present in alkenes but not alkanes? b) draw the structure of an alkene that would not have one of the two bondsarrow_forwardDefine the following terms:(a) Chiral (b) Achiral(c) Chiral carbon (d) Enantiomerarrow_forwardH OH CH2OH D H ОН H الحزن ОН CH2OH ОН H ОН I Which of the following statements correctly describes this structure? (A) The monomer units are bonded by beta 1-2 glycosidic linkage. B The monomer units are bonded by alpha 1-2 glycosidic linkage. The monomer units are bonded by alpha 1-4 glycosidic linkage. The monomer units are bonded by beta 1-4 glycosidic linkage. H CH2OH H ОН H ОН H ОНarrow_forward
- How many peptide bonds were produced by creating the following How many H2O particle were produced by creating the following structure if the starting reagent is glucose? * structure if the starting reagent is glucose? * CH,OH CH,OH CH,OH CH;OH CH;OH CH;OH OH он он OH 250 ÓH OH OH ÓH OH OH 300 А.) 125 B.) 250 А.) 30 c.) 25 B.) 301 D.) 500 C.) 302 E.) O D.) 300 E.) 150 F.) Oarrow_forwardHistidine has three ionizable groups. On the titration curve below, show: a) 2 molar equivalents of OH b) pka of the third ionizable group Histidine Titration 12.0 10.0 8.0 4 pH 6.0 4.0 2.0 0.0 Equivalents OHarrow_forwardExamine the structures of the following molecules. In each compound circle and identify by name each functional group. a) ethanolamine b) Glucosamine c) Threonine H₂N-C-C-OH H₂ H₂ H₂N HO OH d) Phosphoenolpyruvate с H₂N-CH OH OH OH HC - OH 1 CH3 OH T O=P-O O H₂C=C-C OHarrow_forward
- CONH, HQ NH (CH)3C a.) Put asterisk on chiral centers b.) label each chiral center as R or S. c.) Draw the enantiomer d.) Draw one diastereomerarrow_forwardWhat prefixes are used in naming the following?(a) A 1,3-disubstituted benzene(b) A 1,4-disubstituted benzenearrow_forwardWrite chemical names for the following compounds: (a) Thymidine (b) Cytosine (c) Uracil (d) Xanthine (e) Guanine () 2,4-dioxy-6-carboxy pyrimidine (g) CAMP (h) dTTParrow_forward
- BiochemistryBiochemistryISBN:9781319114671Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.Publisher:W. H. FreemanLehninger Principles of BiochemistryBiochemistryISBN:9781464126116Author:David L. Nelson, Michael M. CoxPublisher:W. H. FreemanFundamentals of Biochemistry: Life at the Molecul...BiochemistryISBN:9781118918401Author:Donald Voet, Judith G. Voet, Charlotte W. PrattPublisher:WILEY
- BiochemistryBiochemistryISBN:9781305961135Author:Mary K. Campbell, Shawn O. Farrell, Owen M. McDougalPublisher:Cengage LearningBiochemistryBiochemistryISBN:9781305577206Author:Reginald H. Garrett, Charles M. GrishamPublisher:Cengage LearningFundamentals of General, Organic, and Biological ...BiochemistryISBN:9780134015187Author:John E. McMurry, David S. Ballantine, Carl A. Hoeger, Virginia E. PetersonPublisher:PEARSON