Consider the same two concentric cylinders of Prob. 4-44. This time, however, the inner cylinder is rotating. but the outer cylinder is stationary. In the limit, as the outer cylinder is very large compared to the inner cylinder (imagine the inner cylinder spinning very fast while its radius gets very small), what kind of flow does this approximate? Explain. After a long time has passed, generate an expression for the tangential velocity profile, namely u θ as a function of (at most) ω i , R j , R o , ρ , and μ .. Hint: Your answer may contain an (unknown) constant, which can be obtained by specifying a boundary condition at the inner cylinder surface.
Consider the same two concentric cylinders of Prob. 4-44. This time, however, the inner cylinder is rotating. but the outer cylinder is stationary. In the limit, as the outer cylinder is very large compared to the inner cylinder (imagine the inner cylinder spinning very fast while its radius gets very small), what kind of flow does this approximate? Explain. After a long time has passed, generate an expression for the tangential velocity profile, namely u θ as a function of (at most) ω i , R j , R o , ρ , and μ .. Hint: Your answer may contain an (unknown) constant, which can be obtained by specifying a boundary condition at the inner cylinder surface.
Solution Summary: The author explains the expression for tangential velocity: V=wR_i2r.
Consider the same two concentric cylinders of Prob. 4-44. This time, however, the inner cylinder is rotating. but the outer cylinder is stationary. In the limit, as the outer cylinder is very large compared to the inner cylinder (imagine the inner cylinder spinning very fast while its radius gets very small), what kind of flow does this approximate? Explain. After a long time has passed, generate an expression for the tangential velocity profile, namely
u
θ
as a function of (at most)
ω
i
,
R
j
,
R
o
,
ρ
, and
μ
.. Hint: Your answer may contain an (unknown) constant, which can be obtained by specifying a boundary condition at the inner cylinder surface.
A crate weighs 530 lb and is hung by three ropes attached to
a steel ring at A such that the top surface is parallel to the
xy plane. Point A is located at a height of h = 42 in above
the top of the crate directly over the geometric center of the
top surface. Use the dimensions given in the table below to
determine the tension in each of the three ropes.
2013 Michael Swanbom
↑ Z
C
BY NC SA
b
x
B
у
D
Values for dimensions on the figure are given in the following
table. Note the figure may not be to scale.
Variable Value
a
30 in
b
43 in
с
4.5 in
The tension in rope AB is
lb
The tension in rope AC is
lb
The tension in rope AD is
lb
The airplane weighs 144100 lbs and flies at constant speed
and trajectory given by 0 on the figure. The plane
experiences a drag force of 73620 lbs.
a.) If = 11.3°, determine the thrust and lift forces
required to maintain this speed and trajectory.
b.) Next consider the case where is unknown, but it is
known that the lift force is equal to 7.8 times the quantity
(Fthrust Fdrag). Compute the resulting trajectory angle
-
and the lift force in this case. Use the same values for the
weight and drag forces as you used for part a.
Уллу
Fdrag
10.
Ө
Fthrust
cc 10
2013 Michael Swanbom
BY NC SA
Flift
Fweight
The lift force acts in the y' direction. The weight acts in the
negative y direction. The thrust and drag forces act in the
positive and negative x' directions respectively.
Part (a)
The thrust force is equal to
lbs.
The lift force is equal to
Part (b)
The trajectory angle is equal to
deg.
The lift force is equal to
lbs.
lbs.
The hoist consists of a single rope and an arrangement of
frictionless pulleys as shown. If the angle 0 = 59°, determine
the force that must be applied to the rope, Frope, to lift a
load of 4.4 kN. The three-pulley and hook assembly at the
center of the system has a mass of 22.5 kg with a center of
mass that lies on the line of action of the force applied to the
hook.
e
ΘΕ
B
CC 10
BY NC SA
2013 Michael Swanbom
Fhook
Note the figure may not be to scale.
Frope
=
KN
HO
Frope
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.