
Interpretation: The wavelength required for
Concept Introduction:
Atomic Number :-
Atomic number of the element is equal to the number of protons present in the nucleus of the element which is denoted by symbol Z. The superscript presents on the left side of the
symbol of the element. - First ionization energy:
The ionization energy is the minimum energy required to remove the electron from an isolated atom which is in the gaseous state results to give gaseous ion with one positive charge.
- Cation: Removal of electron from the atom results to form positively charged ion called cation.
- The net charge present in the element denotes the presence or absence of electrons in the element.
- In periodic table the horizontal rows are called periods and the vertical column are called group.
- Plank-Einstein Equation: The energy is conversed property since it can neither be created nor be destroyed but can be transformed. The energy of the photon is obtained by using the following relation
- Wavelength: The distance between the two continuous maximum displacements present in wave or the two continuous minimum displacements present in a wave exhibited by the photons is called wavelength. The wavelength of the photon is inversely proportional to its frequency. The relationship between them is given by the following formula,
- Frequency: It denotes the number of waves passes in given amount of time.
- Visible Range: The
electromagnetic radiation which range is about 390 nm to 700 nm is considered as visible since the human eye can able to detect this range. - UV Range: The electromagnetic radiation which range is about 100 nm to 400nm is regarded as ultraviolet region and they are shorter than the visible region.
To determine: The wavelength in

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Chapter 4 Solutions
Chemistry: Atoms First
- Curved arrows are used to illustrate the flow of electrons. Using the provided starting and product structures, draw the curved electrons-pushing arrows for the following reaction or mechanistic step(s).arrow_forwardCurved arrows are used to illustrate the flow of electrons. Using the provided starting and product structures, draw the curved electron-pushing arrows for the following reaction or mechanistic step(s). Be sure to account for all bond-breaking and bond-making steps. I I I H Select to Add Arrows HCI, CH3CH2OHarrow_forwardCurved arrows are used to illustrate the flow of electrons. Use the reaction conditions provided and the follow the arrows to draw the intermediate and product in this reaction or mechanistic step(s).arrow_forward
- Curved arrows are used to illustrate the flow of electrons. Use the reaction conditions provided and follow the curved arrows to draw the intermediates and product of the following reaction or mechanistic step(s).arrow_forwardCurved arrows are used to illustrate the flow of electrons. Use the reaction conditions provided and follow the arrows to draw the intermediate and the product in this reaction or mechanistic step(s).arrow_forwardLook at the following pairs of structures carefully to identify them as representing a) completely different compounds, b) compounds that are structural isomers of each other, c) compounds that are geometric isomers of each other, d) conformers of the same compound (part of structure rotated around a single bond) or e) the same structure.arrow_forward
- Given 10.0 g of NaOH, what volume of a 0.100 M solution of H2SO4 would be required to exactly react all the NaOH?arrow_forward3.50 g of Li are combined with 3.50 g of N2. What is the maximum mass of Li3N that can be produced? 6 Li + N2 ---> 2 Li3Narrow_forward3.50 g of Li are combined with 3.50 g of N2. What is the maximum mass of Li3N that can be produced? 6 Li + N2 ---> 2 Li3Narrow_forward
- Concentration Trial1 Concentration of iodide solution (mA) 255.8 Concentration of thiosulfate solution (mM) 47.0 Concentration of hydrogen peroxide solution (mM) 110.1 Temperature of iodide solution ('C) 25.0 Volume of iodide solution (1) used (mL) 10.0 Volume of thiosulfate solution (5:03) used (mL) Volume of DI water used (mL) Volume of hydrogen peroxide solution (H₂O₂) used (mL) 1.0 2.5 7.5 Time (s) 16.9 Dark blue Observations Initial concentration of iodide in reaction (mA) Initial concentration of thiosulfate in reaction (mA) Initial concentration of hydrogen peroxide in reaction (mA) Initial Rate (mA's)arrow_forwardDraw the condensed or line-angle structure for an alkene with the formula C5H10. Note: Avoid selecting cis-/trans- isomers in this exercise. Draw two additional condensed or line-angle structures for alkenes with the formula C5H10. Record the name of the isomers in Data Table 1. Repeat steps for 2 cyclic isomers of C5H10arrow_forwardExplain why the following names of the structures are incorrect. CH2CH3 CH3-C=CH-CH2-CH3 a. 2-ethyl-2-pentene CH3 | CH3-CH-CH2-CH=CH2 b. 2-methyl-4-pentenearrow_forward
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