Chapter 4, Problem 4.120QP

The energy needed for the following process is 1.96 × 10⁴ kJ/mol:

$Li\left(g\right)\to L{i}^{3+}\left(g\right)+3e^{-}$

If the first ionization energy of lithium is 520 kJ/mol, calculate the second ionization energy of lithium, that is, the energy required for the process

$L{i}^{+}\left(g\right)\to L{i}^{2+}\left(g\right)+e^{-}$

(Hint: You need the equation in    Problem     4.38.)