Concept explainers
Two pure-breeding strains of summer squash producing yellow fruit,
a. Examine the results of each cross and predict how many genes are responsible for fruit-color determination in summer squash. Justify your answer. b. Using clearly defined symbols of your choice, give the genotypes of parental,
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Genetic Analysis: An Integrated Approach (3rd Edition)
- Suppose that the wild type phenotype for tomatoes is red, round fruit with three-parted leaves and that a strain of mutant tomatoes has yellow, pear-shaped fruit with entire leaves. A and a represent the alleles for fruit color, B and b represent the alleles for fruit shape, and C and c the leaf shape. Two tomatoes with the genotypes Aa Bb cc and Aa Bb CC are crossed. The resulting Punnett square is shown. One cell has been completed with the correct tomato phenotype. Fill in the rest of the Punnett square by placing a fruit and leaf phenotype in each cell. ABC AbC aBC abC ABC Abc aBc abc Answer Bankarrow_forwardFor the cross: PpAa x PpAa P = purple flowers (Dominant) p = white flowers A = axial flowers (Dominant) a = terminal flowers a. What are the possible gamete classes that can form from these parents? b. What are the expected offspring genotype classes and ratios/proportions/fractions which will result from the cross? c. What are the expected offspring phenotype classes and ratios/proportions/fractions which will result from the cross? 2. Predict ratios/proportions/fractions of genotypes and phenotypes of the following crosses. T = tall stem t = dwarf stem P = purple flowers p = white flowers G = green pods g = yellow pods A = axial flowers a = terminal flowers R = round peas r = wrinkled seeds A. ttPp x Ttpp B. GgRr x ggRr C. PpGg x ppggarrow_forwardTwo pure-breeding lines of petunia plants are crossed. Line 1 plants grow to a height of 54 cm, and Line 2 plants grow to a height of 18 cm. Petunia plant height is controlled by three genes, A, B and C. Line 1 has the genotype A₁A₁B₁B₁C₁C₁, and line 2 has the genotype A2A2B₂B₂C₂C₂. Assume that genotype alone determines plant height under ideal growth conditions and that the alleles of the three genes are additive. If the F1 plants are self crossed, what is the expected proportion of F2 plants with the genotype A₁A₁B₁B₁C₁C₁ 1/8 1/32 1/16 1/4 1/64arrow_forward
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- Cross 1 AaBb x AaBb Cross 2 AaBbCc x AaBbCc a) Please use a branching diagram to find the genotypic ratios of the offspring of cross 1 illustrated above and complete with the resulting genotypes and ratios. How many different genotypes are there in the offspring of this cross? [ ] Genotype ratios for the offspring of Cross 1 (please indicate both the ratio and the genotype for each one: e.g.: 3AABB:1aabb, etc): [ ] b) Please use a branching diagram to find the phenotypic ratios of the offspring of cross 2 and complete below the resulting phenotypes and ratios. How many different phenotypes are in the offspring of this cross [ ] Phenotype ratios for the offspring of Cross 2 (please indicate both the ratio and the phenotype for each one using D and R for dominant and recessive phenotypes respectively, for example 1DDD:2DRR, etc.): [ ] c) What mathematical operation are you using to calculate the ratios for multiple genes and what…arrow_forwardA cross was performed using Drosophila melanogaster involving a female known to be heterozygous for both ebony body and sepia eyes and a male known to be homozygous wild type male. The resulting progeny were allowed to mate with one another to produce the data set. Three repetitions of the experiment were conducted. The following data were produced from the crosses. Test these data to determine if they are significantly different from the expected phenotypic ratio. Use the 5% level of significance. Your answer should include the hypothesized cross in genotypes, the Chi-squared value, the critical value and whether you reject or do not reject for each experiment. Wild eye Wild body – 112, Wild eye Ebony body – 40, Sepia eye Wild body – 35, Sepia eye Ebony body – 11arrow_forwardTwo groups of geneticists, in California and in Chile, begin work to develop a linkage map of the medfly. They both independently find that the loci for body color (B = black, b = gray) and eye shape (R = round, r = star) are linked 28 m.u. apart. They send strains to each other and perform crosses; a summary of all their findings is shown here:a. Provide a genetic hypothesis that explains the three sets of testcross results. b. Draw the key chromosomal features of meiosis in the F1 from a cross of the Californian and Chilean lines.arrow_forward
- A pure breeding strain of squash that produced disk-shaped fruits was crossed with a pure- breeding strain having long fruits. The first filial generation had disk fruits, but the second filial generation showed a new phenotype, sphere, and was composed of the following proportions: disk 270, sphere 178, long 32. Propose an explanation for these results, and show the genotypes of P, First filial generation and second filial generation.arrow_forwardE. W. Lindstrom crossed two corn plants with green seedlings and obtained the following progeny: 3583 green seedlings, 853 virescentwhite seedlings, and 260 yellow seedlings (E. W. Lindstrom. 1921. Genetics 6:91–110). a. Give the genotypes for the green, virescent-white, and yellow progeny. b. Explain how color is determined in these seedlings. c. Is there epistasis among the genes that determine color in the corn seedlings? If so, which gene is epistatic and which is hypostatic?arrow_forwardConsider the following dihybrid testcross: B/b • E/e × b/b • e/e For the progeny from this testcross, determine the relative proportions (from 0% to 100%) of each genotype if the two genes: a) are linked (dominant alleles in cis conformation) with no crossing over: Be/be: be/be: BE/be: bE/be: b) assort independently. B/b; E/e: B/b; e/e: b/b; E/e: b/b; e/e: c) are linked (dominant alleles in cis conformation) and 20 map units apart. Be/be: be/be: BE/be: bE/be:arrow_forward
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