You are conducting a single-slit diffraction experiment with light of wavelength λ . What appears, on a distant viewing screen, at a point at which the top and bottom rays through the slit have a path length difference equal to (a) 5 λ and (b) 4.5 λ ?
You are conducting a single-slit diffraction experiment with light of wavelength λ . What appears, on a distant viewing screen, at a point at which the top and bottom rays through the slit have a path length difference equal to (a) 5 λ and (b) 4.5 λ ?
You are conducting a single-slit diffraction experiment with light of wavelength λ. What appears, on a distant viewing screen, at a point at which the top and bottom rays through the slit have a path length difference equal to (a) 5λ and (b) 4.5λ?
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Expert Solution & Answer
To determine
To find:
a) What appears on a distant viewing screen at a point at which the top and bottom rays through the slit have a path length difference equal to 5λ.
b) What appears on a distant viewing screen at a point at which the top and bottom rays through the slit have a path length difference equal to 4.5λ.
Answer to Problem 1Q
Solution:
a) m=5 minimum.
b) Maximum between the m=4 and m=5 (approximately).
Explanation of Solution
1) Concept:
Usingthe condition for occurrence of minimum in a single slit experiment, we can find what appears on a distant viewing screen at a point at which the top and bottom rays through the slit have a path length difference equal to 5λand4.5λ.
2) Formula:
∆L=mλ
3) Given:
The single slit experiment is conducted with the light of wavelength λ.
4) Calculations:
a) In the single slit experiment, the condition for occurrence of minimum is
Pathlengthdifference=∆L=mλForm=1,2,3
From this, we can interpret that at ∆L=5λ;m=5 minimum appears.
b) ∆L=4.5λ implies that it corresponds to approximately maximum between m=4minimumandm=5minimum.
Conclusion:
We can predict about what appears on screen in a single slit experiment from the condition for minimum.
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2. In class, we discussed several different flow scenarios for which we can make enough
assumptions to simplify the Navier-Stokes equations enough to solve them and obtain
an exact solution. Consulting the cylindrical form of the Navier-Stokes equations copied
below, please answer the following questions.
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a.) In class, we discussed how the Navier-Stokes equations are an embodiment of Newton's
2nd law, F = ma (where bolded terms are vectors). Name the 3 forces that we are considering in
our analysis of fluid flow for this class.
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b.) If we make the assumption that flow is "fully developed" in the z direction, which term(s)
would go to zero? Write the term below, describe what the term means in simple language (i.e.
do not simply state "it is the derivative of a with…
1. Consult the form of the x-direction Navier-Stokes equation below that we discussed in
class. (For this problem, only the x direction equation is shown for simplicity). Note that
the equation provided is for a Cartesian coordinate system. In the spaces below, indicate
which of the following assumptions would allow you to eliminate a term from the
equation. If one of the assumptions provided would not allow you to eliminate a
particular term, write "none" in the space provided.
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Assumption
Flow is in the horizontal direction (e.g. patient lying
on hospital bed)
Flow is unidirectional in the x-direction
Steady flow
We consider the flow to be between two flat,
infinitely wide plates
There is no pressure gradient
Flow is axisymmetric
Term(s) in equation
Applications and Investigations in Earth Science (9th Edition)
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Diffraction of light animation best to understand class 12 physics; Author: PTAS: Physics Tomorrow Ambition School;https://www.youtube.com/watch?v=aYkd_xSvaxE;License: Standard YouTube License, CC-BY