Concept explainers
a .
To graph: the given function.
a .
![Check Mark](/static/check-mark.png)
Answer to Problem 40E
Explanation of Solution
Given:
The amount of time (in hours per week) a student utilizes a math-tutoring center roughly follows the
Where x is the number of hours.
The graph of the function
b .
To estimate: the average number of hours per week a student uses the tutoring center.
b .
![Check Mark](/static/check-mark.png)
Answer to Problem 40E
5.4
Explanation of Solution
Given:
The amount of time (in hours per week) a student utilizes a math-tutoring center roughly follows the normal distribution
Where x is the number of hours.
The graph of the function
The average number of hours per week a student uses the tutoring center is given by the x -coordinate of the highest point of the graph.
In this case the x -value corresponding to the maximum y -value is 5.4.
Conclusion:
The average number of hours per week a student uses the tutoring center is 5.4 hours.
Chapter 3 Solutions
EBK PRECALCULUS W/LIMITS
- Perform long division on the integrand, write the proper fraction as a sum of partial fractions, and then evaluate the integral. 30x³-60x²+8 dx 2 x-2x After performing the long division, write the resulting proper fraction as a sum of partial fractions. Evaluate the integral. 30x³-60x²+8 2 x² -2x dx=arrow_forwardEvaluate the following integral. x/6 S tan 2x dx x/12arrow_forwardEvaluate the integral by using a substitution prior to integration by parts. 7) sin (In (6x)) dxarrow_forward
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- review problems please help!arrow_forward3. f(7) 3. Find the domain of each of the following functions. 1 1. f(x)=2-6x+8 2. f(x)=√√7-x 4. A manufacturer has a monthly fixed cost of $40,000 and a production cost of $8 for each unit produced. The product sells for $12 per unit.arrow_forward7. Evaluate the following limits and justify each step. (a) lim (3x²+2x+1) 1 x²+4x-12 (b) lim 1 2 x² - 2x t-√√3t+4 (c) lim t-0 4-t x²-6x+5 (d) lim (e) lim x 5 x-5 x→2 x²+2x+3 4u+1-3 (f) lim u➡2 u-2 1 (g) lim x-3 2 x 55 x - 7x4 +4 (h) lim xx 5x+2x-1 x+1 (i) lim x²-2x+5 - 7x8+4x7 +5xarrow_forward
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