Organic Chemistry
Organic Chemistry
9th Edition
ISBN: 9781305080485
Author: John E. McMurry
Publisher: Cengage Learning
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Chapter 31.SE, Problem 28AP
Interpretation Introduction

Interpretation:

Explain the manufacturing process of nitroethylene by using a distillation column.

Concept introduction:

Nitroethylene is formed by the distillation of 2-nitroethanol in the presence of pthalic anhydride at 140°C-180°C temperature and 80torr pressure.

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The procedure is as follows: Weigh out around 0.3 g of cobalt chloride hexahydrate, CoCl2•6H2O, and place it in a clean, dry beaker. Dissolve it in 20 mL of 95% ethanol (95% ethanol contains about 5% water). Record your observations. Place about 3 mL of the ethanolic cobalt chloride solution in each of five dry test tubes that you have labeled A-E. Place B in a hot water bath. (See figure and instructions below.) Place C in an ice-water bath. Wait a few minutes for them to equilibrate to the temperatures of the baths. Compare the tubes with the control (the ones still at room temperature, i.e. A, D, and E), and record your observations. Add 5 drops of a saturated aqueous sodium chloride solution to D. Observe the result and compare with A. NOTE: any clear or white precipitate that forms in the bottom of this test tube is sodium chloride coming out of solution and is not involved with the chemical reaction that we are studying. Add 3 drops of distilled water to E. Compare with A and D.…
The boiling points for the compounds are 118 °C and 35 °C respectively. The solubility for both compounds is the same (8g/100g water). Explain this observation for (i) boiling point disparity; (ii) solubility similarity H-bonds form in diethyl ether; n-butyl alcohol forms H-bonds in water H-bonds form in n-butyl alcohol; diethyl ether forms H-bonds in water H-bonds in n-butyl alcohol; Both compounds form H-bonds in water O Both compounds form H-bonds; Both compounds form H-bonds in water
5 g of cobalt carbonate and 13 mL of concentrated hydrochloric acid were used. In another glass, prepare a solution with 8.4 mL of anhydrous ethylenediamine and 2.8 mL of concentrated hydrochloric acid. They are mixed and added and 6.5 mL of peroxide were added to it.30% hydrogen, thenconcentrated hydrochloric acid is added, followed by60 mL of ethanol. 5.1234 g were obtained orange solid [Co (en) 3] Cl3 What is the percentage yield of the reaction. The reactions are shown in the images.
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