Concept explainers
(a)
Interpretation:
The IUPAC name for the given alcohol has to be assigned.
Concept Introduction:
IUPAC rules for naming alcohols that contain single hydroxyl group:
- Longest carbon chain has to be identified that contains hydroxyl group also. The chain name is obtained by replacing the letter “-e” in
alkane with “-ol”. - The numbering has to be given so that the hydroxyl group gets the least numbering.
- Name and location of any other substituent present in the chain has to be identified.
- If in a ring the hydroxyl group is present, then that carbon is numbered 1 and the numbering then proceeds counterclockwise or clockwise in a way that substituents present if any gets the least numbering.
- Hydroxyl group as a substituent in a molecule is named as hydroxy group rather than hydroxyl group.
IUPAC rules for naming alcohols that contain more than one hydroxyl group:
- The same rules said above is followed but the prefix di-, tri-, tetra etc is added corresponding to the number of hydroxyl groups that is present.
(b)
Interpretation:
The IUPAC name for the given alcohol has to be assigned.
Concept Introduction:
IUPAC rules for naming alcohols that contain single hydroxyl group:
- Longest carbon chain has to be identified that contains hydroxyl group also. The chain name is obtained by replacing the letter “-e” in alkane with “-ol”.
- The numbering has to be given so that the hydroxyl group gets the least numbering.
- Name and location of any other substituent present in the chain has to be identified.
- If in a ring the hydroxyl group is present, then that carbon is numbered 1 and the numbering then proceeds counterclockwise or clockwise in a way that substituents present if any gets the least numbering.
- Hydroxyl group as a substituent in a molecule is named as hydroxy group rather than hydroxyl group.
IUPAC rules for naming alcohols that contain more than one hydroxyl group:
- The same rules said above is followed but the prefix di-, tri-, tetra etc is added corresponding to the number of hydroxyl groups that is present.
(c)
Interpretation:
The IUPAC name for the given alcohol has to be assigned.
Concept Introduction:
IUPAC rules for naming alcohols that contain single hydroxyl group:
- Longest carbon chain has to be identified that contains hydroxyl group also. The chain name is obtained by replacing the letter “-e” in alkane with “-ol”.
- The numbering has to be given so that the hydroxyl group gets the least numbering.
- Name and location of any other substituent present in the chain has to be identified.
- If in a ring the hydroxyl group is present, then that carbon is numbered 1 and the numbering then proceeds counterclockwise or clockwise in a way that substituents present if any gets the least numbering.
- Hydroxyl group as a substituent in a molecule is named as hydroxy group rather than hydroxyl group.
IUPAC rules for naming alcohols that contain more than one hydroxyl group:
- The same rules said above is followed but the prefix di-, tri-, tetra etc is added corresponding to the number of hydroxyl groups that is present.
(d)
Interpretation:
The IUPAC name for the given alcohol has to be assigned.
Concept Introduction:
IUPAC rules for naming alcohols that contain single hydroxyl group:
- Longest carbon chain has to be identified that contains hydroxyl group also. The chain name is obtained by replacing the letter “-e” in alkane with “-ol”.
- The numbering has to be given so that the hydroxyl group gets the least numbering.
- Name and location of any other substituent present in the chain has to be identified.
- If in a ring the hydroxyl group is present, then that carbon is numbered 1 and the numbering then proceeds counterclockwise or clockwise in a way that substituents present if any gets the least numbering.
- Hydroxyl group as a substituent in a molecule is named as hydroxy group rather than hydroxyl group.
IUPAC rules for naming alcohols that contain more than one hydroxyl group:
- The same rules said above is followed but the prefix di-, tri-, tetra etc is added corresponding to the number of hydroxyl groups that is present.

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Chapter 3 Solutions
EBK ORGANIC AND BIOLOGICAL CHEMISTRY
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- The predominant components of our atmosphere are N₂, O₂, and Ar in the following mole fractions: χN2 = 0.780, χO2 = 0.21, χAr = 0.01. Assuming that these molecules act as ideal gases, calculate ΔGmix, ΔSmix, and ΔHmix when the total pressure is 1 bar and the temperature is 300 K.arrow_forwarddG = Vdp - SdT + μA dnA + μB dnB + ... so that under constant pressure and temperature conditions, the chemical potential of a component is the rate of change of the Gibbs energy of the system with respect to changing composition, μJ = (∂G / ∂nJ)p,T,n' Using first principles prove that under conditions of constant volume and temperature, the chemical potential is a measure of the partial molar Helmholtz energy (μJ = (∂A / ∂nJ)V,T,n')arrow_forwardThe vapor pressure of dichloromethane at 20.0 °C is 58.0 kPa and its enthalpy of vaporization is 32.7 kJ/mol. Estimate the temperature at which its vapor pressure is 66.0 kPa.arrow_forward
- Draw the structure of A, the minor E1 product of the reaction. Cl Skip Part Check F1 esc CH_CH OH, D 3 2 Click and drag to start drawing a structure. 80 R3 F4 F2 F3 @ 2 # $ 4 3 Q W 95 % KO 5 F6 A F7 × G ☐ Save For Later Sub 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy C ►II A A F8 F9 F10 FL 6 7 88 & * 8 9 LLI E R T Y U A S D lock LL F G H 0 P J K L Z X C V B N M 9 Harrow_forwardFrom the choices given, which two substances have the same crystal structure? (Select both) Group of answer choices ZnS (zincblende) Diamond TiO2 (rutile) ZnS (wurtzite)arrow_forwardPotassium (K) blends with germanium (Ge) to form a Zintl phase with a chemical formula of K4Ge4. Which of the following elements would you expect potassium to blend with to form an alloy? Electronegativities: As (2.0), Cl (3.0), Ge (1.8), K (0.8), S (2.5), Ti (1.5) Group of answer choices Arsenic (As) Sulfur (S) Chlorine (Cl) Titanium (Ti)arrow_forward
- Consider two elements, X and Z. Both have cubic-based unit cells with the same edge lengths. X has a bcc unit cell while Z has a fcc unit cell. Which of the following statements is TRUE? Group of answer choices Z has a larger density than X X has more particles in its unit cell than Z does X has a larger density than Z Z has a larger unit cell volume than Xarrow_forwardHow many particles does a face-centered cubic (fcc) unit cell contain? Group of answer choices 2 14 8 4arrow_forwardV Highlight all of the carbon atoms that have at least one beta (B) hydrogen, using red for one ẞ hydrogen, blue for two ẞ hydrogens, and green for three ẞ hydrogens. If none of the carbon atoms have ẞ hydrogens, check the box underneath the molecule. ED X None of the carbon atoms have ẞ hydrogens. Explanation esc 2 Check * F1 F2 1 2 80 # 3 Q W tab A caps lock shift fn control F3 N S option O 694 $ F4 F5 F6 005 % E R D F LL 6 olo 18 Ar B © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accessibility A DII F7 F8 87 & * 8 T Y U G H 4 F9 F10 ( 9 0 E F11 F12 உ J K L + || X C V B N M H H command option commandarrow_forward
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