Concept explainers
(a)
Interpretation:
The given alcohol structures denotes a cis- or trans- isomer has to be indicated.
Concept Introduction:
A cis isomer is the one in which the same groups are present on same side of both the carbon atoms present in the double bond.
A trans isomer is the one in which the same groups are present on opposite side of both the carbon atoms present in the double bond.
Cis‑trans isomerism is not possible if any one of the carbon atom bonded to the double bond bears two identical groups.
Cis‑trans isomers are not constitutional isomers but they are stereoisomers.
Cycloalkanes can also exhibit stereoisomerism. The difference between constitutional isomerism and stereoisomerism is that, the result of difference in connectivity of carbon atoms is known as constitutional isomerism and the result of differences in configuration is known as stereoisomerism. Stereoisomers are compounds that possess same molecular formula and connectivity of atoms but different orientations of atoms in space. Cis isomers are the one where the two substituted groups on different carbon atom are present above or below the plane or the ring of carbon atoms. Trans isomers are the one where the two substituted groups on different carbon atom are present one above and one below the plane or the ring of carbon atoms.
(b)
Interpretation:
The given alcohol structures denotes a cis- or trans- isomer has to be indicated.
Concept Introduction:
Alkenes are hydrocarbons that contain at least one double bond in it. There will not be any free rotation of the double bond in alkene. Hence, cis‑trans isomerism is possible. The first and foremost condition for the alkene to exhibit cis‑trans isomerism is that the carbon attached in either end of double bond must have different groups attached to it.
A cis isomer is the one in which the same groups are present on same side of both the carbon atoms present in the double bond.
A trans isomer is the one in which the same groups are present on opposite side of both the carbon atoms present in the double bond.
Cis‑trans isomerism is not possible if any one of the carbon atom bonded to the double bond bears two identical groups.
Cis‑trans isomers are not constitutional isomers but they are stereoisomers.
Cycloalkanes can also exhibit stereoisomerism. The difference between constitutional isomerism and stereoisomerism is that, the result of difference in connectivity of carbon atoms is known as constitutional isomerism and the result of differences in configuration is known as stereoisomerism. Stereoisomers are compounds that possess same molecular formula and connectivity of atoms but different orientations of atoms in space. Cis isomers are the one where the two substituted groups on different carbon atom are present above or below the plane or the ring of carbon atoms. Trans isomers are the one where the two substituted groups on different carbon atom are present one above and one below the plane or the ring of carbon atoms.
(c)
Interpretation:
The given alcohol structures denotes a cis- or trans- isomer has to be indicated.
Concept Introduction:
Alkenes are hydrocarbons that contain at least one double bond in it. There will not be any free rotation of the double bond in alkene. Hence, cis‑trans isomerism is possible. The first and foremost condition for the alkene to exhibit cis‑trans isomerism is that the carbon attached in either end of double bond must have different groups attached to it.
A cis isomer is the one in which the same groups are present on same side of both the carbon atoms present in the double bond.
A trans isomer is the one in which the same groups are present on opposite side of both the carbon atoms present in the double bond.
Cis‑trans isomerism is not possible if any one of the carbon atom bonded to the double bond bears two identical groups.
Cis‑trans isomers are not constitutional isomers but they are stereoisomers.
Cycloalkanes can also exhibit stereoisomerism. The difference between constitutional isomerism and stereoisomerism is that, the result of difference in connectivity of carbon atoms is known as constitutional isomerism and the result of differences in configuration is known as stereoisomerism. Stereoisomers are compounds that possess same molecular formula and connectivity of atoms but different orientations of atoms in space. Cis isomers are the one where the two substituted groups on different carbon atom are present above or below the plane or the ring of carbon atoms. Trans isomers are the one where the two substituted groups on different carbon atom are present one above and one below the plane or the ring of carbon atoms.
(d)
Interpretation:
The given alcohol structures denotes a cis- or trans- isomer has to be indicated.
Concept Introduction:
Alkenes are hydrocarbons that contain at least one double bond in it. There will not be any free rotation of the double bond in alkene. Hence, cis‑trans isomerism is possible. The first and foremost condition for the alkene to exhibit cis‑trans isomerism is that the carbon attached in either end of double bond must have different groups attached to it.
A cis isomer is the one in which the same groups are present on same side of both the carbon atoms present in the double bond.
A trans isomer is the one in which the same groups are present on opposite side of both the carbon atoms present in the double bond.
Cis‑trans isomerism is not possible if any one of the carbon atom bonded to the double bond bears two identical groups.
Cis‑trans isomers are not constitutional isomers but they are stereoisomers.
Cycloalkanes can also exhibit stereoisomerism. The difference between constitutional isomerism and stereoisomerism is that, the result of difference in connectivity of carbon atoms is known as constitutional isomerism and the result of differences in configuration is known as stereoisomerism. Stereoisomers are compounds that possess same molecular formula and connectivity of atoms but different orientations of atoms in space. Cis isomers are the one where the two substituted groups on different carbon atom are present above or below the plane or the ring of carbon atoms. Trans isomers are the one where the two substituted groups on different carbon atom are present one above and one below the plane or the ring of carbon atoms.

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Chapter 3 Solutions
EBK ORGANIC AND BIOLOGICAL CHEMISTRY
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- Select the stronger base from each pair of compounds. (a) H₂CNH₂ or EtzN (b) CI or NH2 NH2 (c) .Q or EtzN (d) or (e) N or (f) H or Harrow_forward4. Provide a clear arrow-pushing mechanism for each of the following reactions. Do not skip proton transfers, do not combine steps, and make sure your arrows are clear enough to be interpreted without ambiguity. a. 2. 1. LDA 3. H3O+ HOarrow_forwardb. H3C CH3 H3O+ ✓ H OHarrow_forward
- 2. Provide reagents/conditions to accomplish the following syntheses. More than one step is required in some cases. a. CH3arrow_forwardIdentify and provide an explanation that distinguishes a qualitative and quantitative chemical analysis. Provide examples.arrow_forwardIdentify and provide an explanation of the operational principles behind a Atomic Absorption Spectrometer (AAS). List the steps involved.arrow_forward
- Instructions: Complete the questions in the space provided. Show all your work 1. You are trying to determine the rate law expression for a reaction that you are completing at 25°C. You measure the initial reaction rate and the starting concentrations of the reactions for 4 trials. BrO³¯ (aq) + 5Br¯ (aq) + 6H* (aq) → 3Br₂ (l) + 3H2O (l) Initial rate Trial [BrO3] [H*] [Br] (mol/L) (mol/L) | (mol/L) (mol/L.s) 1 0.10 0.10 0.10 8.0 2 0.20 0.10 0.10 16 3 0.10 0.20 0.10 16 4 0.10 0.10 0.20 32 a. Based on the above data what is the rate law expression? b. Solve for the value of k (make sure to include proper units) 2. The proposed reaction mechanism is as follows: i. ii. BrО¸¯ (aq) + H+ (aq) → HBrO3 (aq) HBrO³ (aq) + H* (aq) → H₂BrO3* (aq) iii. H₂BrO³* (aq) + Br¯ (aq) → Br₂O₂ (aq) + H2O (l) [Fast] [Medium] [Slow] iv. Br₂O₂ (aq) + 4H*(aq) + 4Br(aq) → 3Br₂ (l) + H2O (l) [Fast] Evaluate the validity of this proposed reaction. Justify your answer.arrow_forwardе. Д CH3 D*, D20arrow_forwardC. NaOMe, Br Brarrow_forward
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