Concept explainers
a.
To determine: The possible
Introduction: The genotype is the genetic constitution of the organism whereas the phenotype refers to external characters visible in an organism. The alleles are the contrasting forms of a gene, and one of them is dominant, and the other is recessive.
b.
To determine: The possible genotypes for the co-dominant alleles a, b, c, and recessive allele d.
Introduction: The dominant allele masks the expression of the recessive allele. Therefore, the dominant allele is expressed in homozygous and heterozygous genotypes whereas the recessive phenotype is only expressed under homozygous condition.
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Human Heredity: Principles and Issues (MindTap Course List)
- The B allele confers black coat color and the b allele brown coat color in Labrador dogs. When another gene, E, is inherited, the coat is golden no matter what the B phenotype is. A dog of genotype ee expresses the black phenotype. What unusual phenomenon is at work in this disorder?arrow_forwardMendel's Laws of Inheritance Menders Success Menders approach to the study of heredity was effective for several reasons. Foremost was his choice of experimental subject, the pea plant Pisum sativum. Monohybrid Crosses Mendel began by studying monohybrid crosses— those between parents that differed in a single characteristic. The principle of segregation (Mendel's first law) states that each individual diploid organism possesses two alleles for any particular characteristic. These two alleles segregate (separate) when gametes are formed, and one allele goes into each gamete. Furthermore, the two alleles segregate into gametes in equal proportions.The concept of dominance that, when two different alleles are present in a genotype, only the trait of the dominant allele is observed in the phenotype. Multiple-Loci Crosses Dihybrid Crosses In addition to his work on monohybrid crosses, Mendel also crossed varieties of peas that differed in two characteristics (dihybrid crosses).…arrow_forwardIn bears fur colour can be either yellow or tan, and is determined by two alleles of the C gene. A heterozygous bear is observed to present a fur pattern of yellow and tan patches. Explain why this can occur.arrow_forward
- Mendelian Genetics [6F.R]:Question 1 In rabbits, grey fur (G) is dominant to white fur (g) and black eyes (B) are dominant to red eyes (b). A male rabbit with the genotype GgBb is crossed with a female rabbit with the genotype ggbb. What percent of the offspring will have white fur and red eyes? Select one: 25% 50% 100% 0% 1000arrow_forwardchoose only if its a or b no need to explain. 1.) In sex-linked inheritance, if a colour blind man mates with a heterozygous woman, what is the expected ratio of phenotypes among the offsprings? Question 6 options: a.) normal female : heterozygous female : normal male : colour-blind male (1 : 1 : 1 : 1) b.) normal female : normal male : colour-blind male (2 : 1 : 1) c.) normal female : heterozygous female : normal male ( 1 : 1 : 2) d.) heterozygous female: colour blind female: normal male: colour-blind male (1: 1: 1: 1) 2.) The human female has two X chromosomes. In which of the following ways will x-linked traits be inherited among humans? a.) from mother to daughter only b.) from mother to son only c.) from mother to both son and daughter d.) from mother neither to son, nor to daughterarrow_forwardMendelian Genetics Hermione's parents are muggles (cannot perform magic). How is it possible for Hermione to do magic? What are the genotypes of her parents? Is the ability to perform magic dominant or recessive? Hagrid is a half-giant. If his father was a giant, what is the phenotype of his mother? Which trait is dominant?arrow_forward
- Tay–Sachs disease is caused by recessive alleles on anautosome. In which case(s) could two parents with anormal phenotype have a child with Tay–Sachs?a. Both parents are homozygous for a Tay–Sachs allele.b. Both parents are heterozygous for a Tay–Sachsallele.c. One parent is homozygous for a Tay–Sachs allele,and the other is heterozygous.arrow_forwardPart 1: Make a three part process drawing (like a cartoon strip) to demonstrate Mendel’s Principle of Segregation. Use two parents with homologous chromosomes marked with alleles “A” and “a”. Circle and label these three action parts of the Principle of Segregation: a) parents are diploid, b) alleles separate to form haploid gametes (indicate when this happens), and c) gametes from each parent combine at random to form diploid offspring Part 2: Use the cross Aa x Aa and a Punnett square to demonstrate Mendel’s Principle of Segregation. Circle and label these three action parts of the Principle of Segregation: a) parents are diploid, b) alleles separate to form haploid gametes and c) gametes from each parent combine at random to form diploid offspring. Write the expected genotypic and phenotypic ratios.arrow_forwardPart 1: Make a three part process drawing (like a cartoon strip) to demonstrate Mendel's Principle of Segregation. Use two parents with homologous chromosomes marked with alleles "A" and "a". Circle and label these three action parts of the Principle of Segregation: a) parents are diploid, b) alleles separate to form haploid gametes (indicate when this happens), and c) gametes from each parent combine at random to form diploid offspring Part 2: Use the cross Aa x Aa and a Punnett square to demonstrate Mendel's Principle of Segregation. Circle and label these three action parts of the Principle of Segregation: a) parents are diploid, b) alleles separate to form haploid gametes and c) gametes from each parent combine at random to form diploid offspring. Part 3: Use homologous chromosomes marked with alleles "A" and "a" and a second pair of homologs marked with alleles "B" and "b". to demonstrate Mendel's Principle of Independent Assortment in cells in Meiosis. Indicate what phase this…arrow_forward
- In the common daisy, genes A and B control flower color. Both genes have a dominant allele (A or B) and a recessive allele (a or b). At least one copy of each dominant allele is required for flowers to be colorful instead of white. (Explain and Justify your answers) 21.1) Predict the genotypes and phenotypes of the F1 progeny of a cross between two white-flowered plants, one homozygous AA and the other homozygous BB. A) AA bb, white B) aa BB, white C) Aa Bb, colorful D) Aa Bb, white E) aa bb, colorful 21.2) Predict the phenotypic ratio of the F2 progeny of a cross between two white-flowered plants, one homozygous AA and the other homozygous BB. A) 3 colorful : 1 white B) 9 colorful : 7 white C) 9 white : 7 colorful D) 15 white : 1 colorful E) 15 colorful : 1 white 21.3) The inheritance pattern of daisy flower color provides an example of what type of gene interaction? A) additivity…arrow_forwardMendel's observation of the random distribution of two different traits from parents to offspring (giving the 9:3:3:1 ratio of phentypes) was due to A. The random and independent way in which each pair of homologous chromosomes lines up at the metaphase plate during meiosis I. B. The random nature of the fertilization of ova by sperm. C. The random distribution of the sister chromatids to the two daughter cells during anaphase II. D. The relatively small degree of homology shared by the X and Y chromosomes.arrow_forwardMendelian Genetics and Non-Mendelian Genetics: Huntington’s disease, a neurodegenerative genetic disorder that typically becomes noticeable in middle age, is due to an autosomal dominant allele. Sickle cell anemia, on the other hand, is a genetic blood disorder due to a recessive allele. Jillian is a carrier of the allele for sickle cell anemia but has no sign of any neurodegenerative disorder in her family. She married Jacobwhose father died of Huntington’s disease. His mother, however, is not inflicted with that condition. Neither of his parents exhibit sickle cell anemia. 1. Give the genotypes of Jillian and Jacob. Assuming that they will have 4 children, what is the probability that: 2. all their children will be normal? 3. they will have a son with Huntington’s disease? 4. they will have a daughter inflicted with both conditionsarrow_forward
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